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Anastaziya [24]
3 years ago
11

How large a container, in liters, would you need to hold 7.2 kg of gasoline? (Take the density of gasoline to be 0.68 g/cm³.)

Chemistry
1 answer:
Mamont248 [21]3 years ago
7 0

Answer:

Volume = mass / density

V = 7200 / 0.68 (ensure units are consistent)

V = 10588 cm^3

=>approx 10600 cm^3

V = 10.6 litres

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ivanzaharov [21]
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3 years ago
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What size volumetric flask would you use to create a 0.50 M<br> solution using 10.00 g of CaBr2
SIZIF [17.4K]

Answer:

Explanation:

First convert the grams of Calcium Bromide to moles by using the atomic weight. Then use the formula for molarity, which is moles per liter.

CaBr2 = 199.9 g/mol

10/199.9 = 0.05 moles of CaBr2

0.5M=\frac{0.05mol}{x}

x = 0.1L or 100mL

5 0
3 years ago
When 3.00 moles of hydrogen molecules and 1.50 moles of oxygen molecules react, they form 3.00 moles of water according to the r
Luden [163]

Answer:

The answer to your question is: 6 grams of hydrogen

Explanation:

Data

3.0 moles of hydrogen

1.5 moles of oxygen

3 moles of water

# of grams of hydrogen required to form 3 moles of water?

Equation

                  H₂    +   1/2 O₂        ⇒        H₂O

                3 mole    1.5 moles           3 moles

 Atomic weight of H₂ = 2 g

                         1 mole -----------------------   2 g

                         3 moles ---------------------    x

                          x = 3(2)/1 = 6 grams of hydrogens

3 0
3 years ago
Pls help I’m failing this class
elena55 [62]
The answer is a conductor. Metals are good conductors of heat. ... the close packing of the metal ions in the lattice. the delocalised electrons can carry kinetic energy through the lattice.
6 0
3 years ago
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A solution of saturated pbi2 is found to contain 2.7 ✕ 10−3 m iodide ion. calculate the ksp of pbi2
BigorU [14]
When the compound PbI₂ dissolves, it dissociates as follows;
PbI₂ --> Pb²⁺ + 2I⁻
Molar solubility is the number of moles dissolved in 1 L of solution
A saturated solution is when the maximum amount of solute is dissolved in the solution.
Molar solubility of Iodide when solution is saturated is 2.7 x 10⁻³ mol/L, then solubility of Pb²⁺ is (2.7 x 10⁻³ mol/L) / 2 = 1.35 x 10⁻³ mol/L
ksp is the solubility product constant that can be calculated as follows;
ksp = [Pb²⁺][I⁻]
ksp = (1.35 x 10⁻³ mol/L) x (2.7 x 10⁻³ mol/L)²
      = 1.35 x 10⁻³ x 7.29 x 10⁻⁶
      = 9.8 x 10⁻⁹ 
4 0
4 years ago
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