Natural, Whole, and Integers. Hopefully I helped :)
Answer:
Third graph down
Step-by-step explanation:
2x -6 ≥ 6(x-2)+8
Distribute
2x - 6≥6x -12+8
Combine like terms
2x - 6≥6x -4
Subtract 2x from each side
2x-6-2x ≥6x-2x-4
-6 ≥4x-12
Add 4 to each side
-6+4 ≥4x-4+4
-2 ≥4x
Divide by 4
-2/4 ≥4x/4
-1/2≥x
Closed circle at -1/2
Line going the the left
To help you out I save your picture and explain the process. The only thing tht confuses me is problem #!6. But I hope I helped you out in the slightest bit
Answer:
There is no solution for this set of equations.
The sum of two numbers can not have two different solutions.
Answer:
-29m+62n
Step-by-step explanation:
5 (3m+6n)-4 (11m-8m)
15m+30n-44m+30n
15m-44m +32n+30n
-29m +62n
