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posledela
3 years ago
5

Pls help the person with the correct answer gets a brainliest

Mathematics
1 answer:
borishaifa [10]3 years ago
3 0

Answer:

21

Step-by-step explanation:

Good luck ..have a nice day

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Last one for the class...
tigry1 [53]

Hope this helps!

Sorry the writing is really bad looking its hard to write on a laptop.

5 0
3 years ago
Many utility companies promote energy conservation by offering discount rates to consumers who keep their energy usage below cer
aleksley [76]

Answer:

a. 0.1681 = 16.81% probability that all five qualify for the favorable rate.

b. 0.5283 = 52.83% probability that at least four qualify for the favorable rates

Step-by-step explanation:

For each Puerto Rico resident, there are only two possible outcomes. Either they qualify for discounted rates, or they do not. The probability of a person in the sample qualifying for discounted rates is independent of any other person in the sample. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

70% of the island residents of Puerto Rico have reduced their electricity usage sufficiently to qualify for discounted rates.

This means that p = 0.7

Five residential subscribers are randomly selected from San Juan, Puerto Rico

This means that n = 5

a. All five qualify for the favorable rate

This is P(X = 5). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{5,5}.(0.7)^{5}.(0.3)^{0} = 0.1681

0.1681 = 16.81% probability that all five qualify for the favorable rate.

b. At least four qualify for the favorable rates

This is

P(X \geq 4) = P(X = 4) + P(X = 5)

So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 4) = C_{5,4}.(0.7)^{4}.(0.3)^{1} = 0.3602

P(X = 5) = C_{5,5}.(0.7)^{5}.(0.3)^{0} = 0.1681

P(X \geq 4) = P(X = 4) + P(X = 5) = 0.3602 + 0.1681 = 0.5283

0.5283 = 52.83% probability that at least four qualify for the favorable rates

5 0
3 years ago
please answer fast!!! drag each figure to show if it is similar to the figure shown or why it is not similar
igomit [66]

Answer:

The similar figures are shown in the attached drawing created with Microsoft Visio;

The similar figures are the rectangles in figures 2, and 5

Step-by-step explanation:

The given figure is a rectangle with dimensions of 3 yd. by 9 yd., therefore the length = 3 × The width of the rectangle

1) The 9 yd. by 18 yd. figure is a rectangle with the length = 2 × The width of the rectangle, therefore, the figure is not similar to the given rectangle

2) The 3 yd. by 1 yd. figure is a rectangle with the width = 3 × The length of the rectangle, therefore, the figure is similar to the given rectangle

3) The figure is a trapezium, while the given figure is a rectangle, therefore, they are not similar

4) The 6 yd. by 3 yd. figure is a rectangle with the width = 2 × The length of the rectangle, therefore, the figure is not similar to the given rectangle

5) The 6 yd. by 18 yd. figure is a rectangle with the length = 3 × The width of the rectangle, therefore, the figure is similar to the given rectangle

6) The 2 yd. by 8 yd. figure is a rectangle with the length = 4 × The width of the rectangle, therefore, the figure is not similar to the given rectangle

3 0
2 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B5%7D%20%20-%203" id="TexFormula1" title=" \frac{1}{5} - 3" alt=" \frac{1}
denis-greek [22]
-14/5 , -2.8 and yeah
3 0
3 years ago
If P = {3, 5, 7, 11, 13, 17, 19), what is n(P)?
Darina [25.2K]

Answer:

the n(P) of P = {3, 5, 7, 11, 13, 17, 19} is "128".

Step-by-step explanation:

n(P) is the <u>Cardinality</u> of the set P. Its formula is 2^k.

where k = number of elements in the set.

Hope this helps :)

7 0
2 years ago
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