Answer:
9.99 years
Step-by-step explanation:
P=$3,500
r=7%=0.07
n=4(quarterly)
A= double of $3,500=
$3,500×2=$7,000
t=?
A=p(1+r/n)^nt
$7,000=$3,500(1+0.07/4)^4t
$7,000=$3,500(1+0.0175)^4t
$7,000=$3,500(1.0175)^4t
Divide both sides by $3,500
2=(1.0175)^4t
Take the log to base 10 of both sides
log2=4t × log1.0175
0.30103=4t × 0.00753
0.30103=4(0.00753)t
0.30103=0.03012t
t=0.30103/0.03012
t=9.99435
Approximately
9.99 years
f(n) is the nth term
Each term f(n) is found by adding the terms just prior to the nth term. Those two terms added are f(n-1) and f(n-2)
The term just before nth term is f(n-1)
The term just before the (n-1)st term is f(n-2)
----------------
For example, let's say n = 3 indicating the 3rd term
n-1 = 3-1 = 2
n-2 = 3-2 = 1
So f(n) = f(n-1) + f(n-2) turns into f(3) = f(2) + f(1). We find the third term by adding the two terms just before it.
f3) = third term
f(2) = second term
f(1) = first term
1. For every ounce of fertilizer 2.5 more pepper pods can be expected.
2. When no fertilizer is added, 4 pepper pods can be expected.
3. 8 pepper pods. Plug in 1.6 for X: y=2.5(1.6)+4=8
To solve this problem, we must substitute each variable a in the expression with a 4 and each variable b in the expression with a 3. This is modeled below:
(ab)2
(4*3)2
To simplify, we must remember to use the order of operations, which is outlined by PEMDAS. This tells us that we should compute numbers in parentheses first, exponents next, then multiplication and division, and finally addition and subtraction. In this example, we are going to compute what is in the parentheses first.
(4*3)2
12 * 2
Next, we can solve using multiplication.
24
Therefore, your answer is 24.
Hope this helps!
Answer:
"cinco es menor o igual que diez, y dos más dos son cuatro"
Step-by-step explanation:
Primero definamos los simbolos utilizados.
∧ significa "y"
∼ es el simbolo de la negación, es decir:
∼p significa "no p"
terminemos de resolver el problema para que el concepto quede claro.
si:
p = cinco es mayor que diez (5 > 10)
entonces:
∼p = cinco es menor o igual que diez (5 ≤ 10)
y
q = dos más dos son cuatro. (2 + 2 = 4)
entonces:
∼p∧q se escribe como:
"cinco es menor o igual que diez, y dos más dos son cuatro"