Question

The temperature at 6:00 a.m. was ‐3.5°C. From 6:00 to 7:00, the temperature increased 2.5°C. From 7:00 to 8:00, it decreased by 0.25°C, and from 8:00 to 11:00, the temperature dropped 3.25°C. Which expression shows the temperature in °C at 11:00 a.m.?

Answer 1

The expression that shows the temperature in °C is $-3.5+2.5+(-0.25)+(-3.25)$.

Step-by-step explanation:

Step 1:

The initial temperature at 6.00 am was $-3.5$ °C.

Step 2:

From 6.00 to 7.00 am, the temperature increased by another 2.5°C, so the temperature at 7.00 am was $(-3.5 + 2.5)$ °C.

Step 3:

From 7.00 to 8.00 a.m, the temperature decreased by another 0.25°C, so the temperature at 8.00 am was $(-3.5+2.5+(-0.25))$ °C.

Step 4:

From 8.00 to 11.00 a.m, the temperature dropped by another 3.25 °C, so the temperature at 11.00 am was $(-3.5+2.5+(-0.25)+-(3.25))$ °C which is represented by the fourth option.