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vova2212 [387]
4 years ago
7

Simplify: 3[2(6 + 4)-8]+8÷2

Mathematics
1 answer:
Diano4ka-milaya [45]4 years ago
8 0
<span>3[2(6 + 4)-8]+8÷2

Inner most bracket (6 + 4):
= </span><span>3[2(10)-8]+8÷2

Multiplication within the bracket (2(10)):
</span>= 3[20-8]+8÷2

Bracket (20 - 8):
= 3[12]+8÷2

Multiplication (3(12)):
= 36+8÷2

Division (8÷2):
= 36+4

Add (36 + 4):
=40

Answer: 40

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Step-by-step explanation:

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2 years ago
8b-ab=7a, .subtracted from 3a-9ab+b<br>​
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Step-by-step explanation:

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3 0
3 years ago
b) Would you consider it unusual to find a college student who never wears a seat belt when riding in a car driven by someone​ e
PilotLPTM [1.2K]

Answer:

Step-by-step explanation:

Hello!

<em>Full text</em>

<em>In a national survey college students were​ asked, "How often do you  wear a seat belt when riding in a car driven by someone​ else?" The response frequencies appear in the table to the right.​ (a) Construct a probability model for​ seat-belt use by a passenger.​ (b) Would you consider it unusual to find a college student who never wears a seat belt when riding in a car driven by someone​ else? </em>

<em>Response , Frequency   </em>

<em>Never  102 </em>

<em>Rarely  319 </em>

<em>Sometimes  524 </em>

<em>Most of the time  1067 </em>

<em>Always  2727 </em>

n= 102+319+524+1067+2727= 4739

<em> ​(a) Complete the table below. </em>

<em>Response </em>

<em>Probability  </em>To calculate the probability for each response you have to divide the frequency of each category by the total of people surveyed:

<em>Never </em> P(N)= 102/4739= 0.0215

<em>​(Round to the nearest thousandth as​ needed.) </em>

<em>Rarely </em> P(R)= 319/4739= 0.0673

<em>​(Round to the nearest thousandth as​ needed.) </em>

<em>Sometimes </em> P(S)= 524/4739= 0.1106

<em>​(Round to the nearest thousandth as​ needed.) </em>

<em>Most of the time  </em>P(M)= 1067/4739= 0.2252

<em>​(Round to the nearest thousandth as​ needed.) </em>

<em>Always  </em>P(A)= 2727/4739= 0.5754

<em>​(Round to the nearest thousandth as​ needed.) </em>

<em />

<em>​(b) Would you consider it unusual to find a college student who never wears a seat belt when riding in a car driven by someone​ else? </em>

<em>A. </em>

<em>​No, because there were 102  people in the survey who said they never wear their seat belt. </em> Incorrect, an event is considered unusual if its probability (relative frequency) is low, you cannot know if it is usual or unusual just by looking at the absolute frequency of it.

<em>B. </em>

<em>​Yes, because ​P(never) < 0.05. </em> Correct

<em> C. </em>

<em>​No, because the probability of an unusual event is 0.    </em>Incorrect, the probability of unusual events is low, impossible events are the ones with probability zero

<em>D. </em>

<em>​Yes, because 0.01 < ​P(never) <  0.10. </em>Incorrect, by the definition an event is considered unusual when its probability is equal or less than 5%.

I hope this helps!

3 0
3 years ago
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