Substitute y = 2x - 4 to x + 2y = 12:
x + 2(2x - 4) = 12 <em>use distributive property</em>
x + (2)(2x) + (2)(-4) = 12
x + 4x - 8 = 12 <em>add 8 to both sides</em>
5x = 20 <em>divide both sides by 5</em>
x = 4
Put the value of x to the first equation:
y = 2(4) - 4
y = 8 - 4
y = 4
<h3>Answer: x = 4 and y = 4</h3>
Answer:
I think its 4 and 5
Step-by-step explanation:
Answer:
r = √13
Step-by-step explanation:
Starting with x^2+y^2+6x-2y+3, group like terms, first x terms and then y terms: x^2 + 6x + y^2 -2y = 3. Please note that there has to be an " = " sign in this equation, and that I have taken the liberty of replacing " +3" with " = 3 ."
We need to "complete the square" of x^2 + 6x. I'll just jump in and do it: Take half of the coefficient of the x term and square it; add, and then subtract, this square from x^2 + 6x: x^2 + 6x + 3^2 - 3^2. Then do the same for y^2 - 2y: y^2 - 2y + 1^2 - 1^2.
Now re-write the perfect square x^2 + 6x + 9 by (x + 3)^2. Then we have x^2 + 6x + 9 - 9; also y^2 - 1y + 1 - 1. Making these replacements:
(x + 3)^2 - 9 + (y - 1)^2 -1 = 3. Move the constants -9 and -1 to the other side of the equation: (x + 3)^2 + (y - 1)^2 = 3 + 9 + 1 = 13
Then the original equation now looks like (x + 3)^2 + (y - 1)^2 = 13, and this 13 is the square of the radius, r: r^2 = 13, so that the radius is r = √13.
Answer:
b(4) = -8
Step-by-step explanation:
We are to find the 4th term.
n = 4
b(n) = 1(-2)ⁿ⁻¹
b(4) = 1(-2)⁴⁻¹
b(4) = 1(-2)³
b(4) = 1(-8)
b(4) = -8
