Complete Question
Ava read an article claiming that 10% of people in her county were senior citizens, and she wondered if this held true for residents in her city. She took a random sample of 225 people from her city to test H0 : p = 0.10, where p is the proportion of people in her city that are senior citizens. Ava found that approximately 14% of those sampled were senior citizens. She conducted an appropriate significance test, and the resulting test statistic was z ≈ 1.89 z. Assume that the conditions for inference were met.calculate the p-value for Ellie's significance test
Answer:
The p-value is 
Step-by-step explanation:
From the question we are told that
The percentage of senior citizens is p = 0.10
The sample size is 
The sample proportion is 
The test statistics is 
The null hypothesis is 
The alternative hypothesis is 
Generally the p-value is mathematically represented as

From the z-table

=> 
=> 
1. 2/5 x 3/4
1/5 x 3/2
3/10
2.-20x(-6)
multiplying two negatives equals a positive so
20x6=120
3.
A. -4
B.-20
C. Absolute value is always positive
4x2-3+15
8-3+15=20
Answer:
1.39
Step-by-step explanation:
Creating a table:
X :___0 __ 1 __ 2 ___ 3 ____ 4 ___ 5 ___ 6
P(x):0.02_0.03_0.07, 0.12, 0.30_ 0.28_0.18.
The standard deviation = sqrt(Var(x))
Var(x) = Σx²*p(x) - E(x)²
E(x) = ΣX*p(x)
E(x) = (0*0.02) + (1*0.03) + (2*0.07) + (3*0.12) + (4*0.30) + (5*0.28) + (6*0.18) = 4.21
Var(X) :
((0^2*0.02) + (1^2*0.03) + (2^2*0.07) + (3^2*0.12) + (4^2*0.30) + (5^2*0.28) + (6^2*0.18)) - 4.21^2
19.67 - 17.7241
= 1.9459
Standard deviation = sqrt(Var(X))
Standard deviation = sqrt(1.9459)
Standard deviation = 1.3949551
= 1.39
"Away from lift off 3 seconds". meaning explanation has to start off with proper vocabulary to identify what is being explained.