Algebra 1 pleaseeeeeeee help me

Gina has 21 more barrettes than Holly. The equation g = 21 + h, where g represents the number of barrettes Gina has, and h repre

kompoz [17]

Answer:

21

Step-by-step explanation:

42-21=21

8 0

3 years ago

Read 2 more answers

Given the function f)(x) =-x^2+3x+8,determine the average rate of change of the function over the interval listed in the picture

Nadusha1986 [10]

Answer:

Vertex:

(

3

2

,

−

41

4

)

(

3

2

,

-

41

4

)

Focus:

(

3

2

,

−

10

)

(

3

2

,

-

10

)

Axis of Symmetry:

x

=

3

2

x

=

3

2

Directrix:

y

=

−

21

2

y

=

-

21

2

x

y

0

−

8

1

−

10

3

2

−

41

4

3

−

8

4

−

4

Vertex:

(

3

2

,

−

41

4

)

(

3

2

,

-

41

4

)

Focus:

(

3

2

,

−

10

)

(

3

2

,

-

10

)

Axis of Symmetry:

x

=

3

2

x

=

3

2

Directrix:

y

=

−

21

2

y

=

-

21

2

x

y

0

−

8

1

−

10

3

2

−

41

4

3

−

8

4

−

4

Step-by-step explanation:

7 0

3 years ago

Determine the equations of the vertical and horizontal asymptotes, if any, for y=x^3/(x-2)^4

djverab [1.8K]

Answer:

Option a)

Step-by-step explanation:

To get the vertical asymptotes of the function f(x) you must find the limit when x tends k of f(x). If this limit tends to infinity then x = k is a vertical asymptote of the function.

$\lim_{x\to\\2}\frac{x^3}{(x-2)^4} \\\\\\lim_{x\to\\2}\frac{2^3}{(2-2)^4}\\\\\lim_{x\to\\2}\frac{2^3}{(0)^4} = \infty$

Then. x = 2 it's a vertical asintota.

To obtain the horizontal asymptote of the function take the following limit:

$\lim_{x \to \infty}\frac{x^3}{(x-2)^4}$

if $\lim_{x \to \infty}\frac{x^3}{(x-2)^4} = b$ then y = b is horizontal asymptote

Then:

$\lim_{x \to \infty}\frac{x^3}{(x-2)^4} \\\\\\lim_{x \to \infty}\frac{1}{(\infty)} = 0$

Therefore y = 0 is a horizontal asymptote of f(x).

Then the correct answer is the option a) x = 2, y = 0

3 0

4 years ago

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For what value of x does g(x) = 0???

Lunna [17]

g(x) = 0

This is asking at what x value does y = 0. g(x) = y

y = 0, when x is 6

7 0

3 years ago

PLEASE HELP ASAP (8)/(27) a^(15) cube of a monomial

vagabundo [1.1K]

Answer:

2/3a^5

Step-by-step explanation:

we know that 2/7x2/7x2/7 = 8/27

a^15 cube will be a^5

because we know (2^3)^2 = 2^6

so (a^5)^3 = a^15

2/3a^5

4 0

3 years ago