Answer:
The fraction of the offspring that will show the phenotype produced by the recessive c allele is 1024/4096 = 0.25 A-BbccDdE-Ff = 25%
Explanation:
You can calculate the fraction of the offspring that will show the phenotype produced by the recessive c allele by making the punnet square for each gene and then multipling the phenotypic proportions, like this:
Cross) AAbbCcDDEeff x AaBBCcddEEFF
Cross For each gene by separately:
Gametes) A A A a
F1) 2/4 AA
2/4 Aa
Gametes) b b B b
F1) 4/4 Bb
Gametes) C c C c
F1) 1/4 CC
2/4 Cc
1/4 cc
Gametes) D D d d
F1) 4/4 Dd
Gametes) E e E E
F1) 2/4 Ee
2/4 EE
Gametes) f f F F
F1) 4/4 Ff
So, fraction of the offspring that will show the phenotype produced by the recessive c allele is:
4/4 A- x 4/4 Bb x 1/4 cc x 4/4 Dd x 4/4 E- x 4/4 Ff =
1024/4096 = 0.25 A-BbccDdE-Ff =25%
Answer;
-PET scan
A PET scan uses radioactive markers in the blood to monitor blood flow and metabolic activity via x-ray
Explanation;
-A positron emission tomography (PET) scan is an imaging test that helps reveal how the tissues and organs are functioning. A PET scan uses a radioactive drug (tracer) to show this activity. This scan can sometimes detect disease before it shows up on other imaging tests.
-A PET scan is used to diagnose certain health conditions, to plan treatment, to find out how an existing condition is developing, and to see how effective a treatment is.
-In a PET scan, a machine detects radiation that is emitted by a radiotracer. A radiotracer consists of radioactive material that is tagged to a natural chemical, such as glucose.
The correct answer is "anisocoria". Anisocoria is the condition when the patient's pupils are normally unequal and the patient is asymptomatic and clinically stable. This should be differentiated in cases of patient with a relative afferent pupillary defect such is patients with optic neuritis or retinal detachment or in patients with neurological deficits.
Hello, this would be known as Eye Tabbing.
Hope this helps<3
