Question

The figures show the dimensions of a tennis court and a basketball court given in terms of the width in feet of the tennis court. Also need help with a,b,and c

Answer 1

Answer:

a.  Perimeter of the tennis court = 6x + 12

Perimeter of the Basketball court = 7x + 36

b.  x + 24

c.  Length of the tennis court = 78 feet

Width of the tennis court = 36 feet

Length of the Basketball court = 94 feet

Width of the Basketball court = 50 feet

Step-by-step explanation:

a.  Perimeter of the rectangle = 2(length + width)

So, perimeter of the tennis court = 2[(2x + 6) + x]

= 2(3x + 6)

= 6x + 12

Perimeter of the Basketball court = 2[(3x - 14)+($\frac{1}{2}$x + 32)]

= 6x - 28 + x + 64

= 7x + 36

b.  Perimeter of the Basketball court - perimeter of the tennis court

= (7x + 36) - (6x + 12)

= 7x + 36 - 6x - 12

= x + 24

So, perimeter of the basketball court is x + 24 feet greater than that of the tennis court

c.  It is given that the width of the tennis court = 36 feet

But, from the figure,

width of the tennis court = x

So, x = 36

Therefore, length of the tennis court = 2x + 6

= 2(36) + 6

= 72 + 6

= 78 feet

Width of the tennis court = x = 36 feet

Length of the basketball court = 3x - 14

= 3(36) - 14

= 108 - 14

= 94 feet

Width of the basketball court = $\frac{1}{2} x+32$

$=\frac{1}{2} (36)+32$

= 18 + 32

= 50 feet