The figures show the dimensions of a tennis court and a basketball court given in terms of the width in feet of the tennis court
. Also need help with a,b,and c
1 answer:
Answer:
a. Perimeter of the tennis court = 6x + 12
Perimeter of the Basketball court = 7x + 36
b. x + 24
c. Length of the tennis court = 78 feet
Width of the tennis court = 36 feet
Length of the Basketball court = 94 feet
Width of the Basketball court = 50 feet
Step-by-step explanation:
a. Perimeter of the rectangle = 2(length + width)
So, perimeter of the tennis court = 2[(2x + 6) + x]
= 2(3x + 6)
= 6x + 12
Perimeter of the Basketball court = 2[(3x - 14)+(x + 32)]
= 6x - 28 + x + 64
= 7x + 36
b. Perimeter of the Basketball court - perimeter of the tennis court
= (7x + 36) - (6x + 12)
= 7x + 36 - 6x - 12
= x + 24
So, perimeter of the basketball court is x + 24 feet greater than that of the tennis court
c. It is given that the width of the tennis court = 36 feet
But, from the figure,
width of the tennis court = x
So, x = 36
Therefore, length of the tennis court = 2x + 6
= 2(36) + 6
= 72 + 6
= 78 feet
Width of the tennis court = x = 36 feet
Length of the basketball court = 3x - 14
= 3(36) - 14
= 108 - 14
= 94 feet
Width of the basketball court =
= 18 + 32
= 50 feet
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Answer:
D. Kelsey graphed the slope as the y-intercept and the y-intercept as the slope.
Step-by-step explanation:
The equation to graph was : y= 3x + 1 where the slope is 3 and the y-intercept is 1
However, Kelsey graph line passes through points (-3, 0)and (0, 3).From these points the equation of the line is;
m=Δy/Δx where
m=the slope of the graph
Δy= 3-0 =3
Δx= 0--3 =3
m=3/3 = 1
The equation of the line should be;
m=Δy/Δx
1=y-3/x-0
1x= y-3
3+1x= y
y= 1x + 3 ----------where the slope is 1 and y-intercept is 3
So you can see here that in the original equation,<em> the slope m is 3 and y-intercept is 1 as shown in the first attached graph.</em>
While in the Kelsey's graph, <em>the slope is 1 and the y-intercept is 3 as in the second attached graph. </em>
<em>Thus, the correct answer is D : Kelsey graphed </em><u><em>the slope,3</em></u><em> as the </em><em>y-intercept </em><em>and the</em><u><em> y-intercept,1,</em></u><em> as the slope. </em>
Answer choice A is incorrect because Kelsey didnot graph the y-intercept, 1 on the x-axis but graphed point (-3,0) on the x-axis.
Answer choice B is incorrect because on Kelsey's equation the y-intercept is 3 and not -3. i.e. y=1x + 3
Answer choice C is incorrect because Kelsey graphed the slope as up 1 right 1 which is okay per the equation , y=1x+3.However, this incorrect because the correct graph has a slope of 3.
