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Alex
3 years ago
9

What is e+2 I don’t understand can someone help me pleaseeee

Mathematics
1 answer:
Nina [5.8K]3 years ago
8 0

Answer:

the answer should be 4.71828182846

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Point-slope equation of the line through (6,4) and (7,2)
Nataly [62]

Answer:

<h2>y - 4 = -2(x - 6) or y - 2 = -2(x - 7)</h2>

Step-by-step explanation:

The point-slope form of an equation of a line:

y-y_1=m(x-x_1)

m - slope

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (6, 4) and (7, 2). Substitute:

m=\dfrac{2-4}{7-6}=\dfrac{-2}{1}=-2

Using the first point

y-4=-2(x-6)

Using the second point

y-2=-2(x-7)

7 0
4 years ago
A statistician calculates the mean from several random surveys, each of adults in Virginia, to find out the most frequent type o
irakobra [83]

Answer:

i think its 21

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
A thermometer is guaranteed to give a temperature no more than 12 degree Fahrenheit from the actual temperature. If the thermome
andrew11 [14]

So let T be the max and min temperature, and let x be the given temperature in °F.
T = x+-12
So for this case the Tmax will be 40°F using the equation above.
And Tmin being 16°F

4 0
4 years ago
Quadrilateral ABCD ​ is inscribed in this circle.
Sedbober [7]
The answer to this is 65. 

Remember that the angles opposite of each other equal to 180. So a+c=180 and b+d=180. 

First, we solve for x. Since we know that b and d equal to 180, we subtract 148 from 180. 
180-148=32. x=32. 

Then we plug that in the expression for angle a. 
2x+1 becomes 2(32)+1
2*32=64
64+1=65.
a=65
4 0
3 years ago
A population of 6000 animals decrease at an annual rate of 0.7%. What is the expected population in 12 years? Round your answer
solmaris [256]

Answer:

The population is expected to be 5515 animals in 12 years.

Step-by-step explanation:

This problem can be solved by using a compounded interest formula with a negative interest rate, since the number of animals are decreasing. We have:

final population = initial population * (1 - r)^(t)

Where r is rate of decline and t is the time elapsed. Applying the data from the question we have:

final population = 6000*(1 - 0.007)^(12)

final population = 6000*(0.993)^12 = 5514.9582 animals

The population is expected to be 5515 animals in 12 years.

6 0
4 years ago
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