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3 years ago

8

A gymnasium can hold no more than 650 people.A permanent bleacher in the gymnasium holds 136 people. The event organizers are se

tting up 25 rows with an equal number of chairs.At most, how many chairs can be in each row

2 answers:

zhenek [66]3 years ago

5 0

Answer:

20

Step-by-step explanation:

nope

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ValentinkaMS [17]3 years ago

3 0

Answer:

20 chairs

Step-by-step explanation:

After 136 people are seated in the bleacher, there can be 514 people seated in chairs. We know that 514 = 25×20 +14, so there can be 20 rows of 25 chairs. We require an equal number of chairs in each row, so there cannot be some rows with 21 chairs, nor can there be a 26th row with 14 chairs.

There can be 20 chairs in each row.

You might be interested in

What is the quotient when 4x3 + 2x + 7 is divided by x + 3?

Arte-miy333 [17]

Answer:

The quotient of this division is $(4x^2 -12x + 38)$ . The remainder here would be $-26$ .

Step-by-step explanation:

The numerator $4x^3 + 2x + 7$ is a polynomial about $x$ with degree $3$ .

The divisor $x + 3$ is a polynomial, also about $x$ , but with degree $1$ .

By the division algorithm, the quotient should be of degree $3 - 1 = 2$ , while the remainder shall be of degree $1 - 1 = 0$ (i.e., the remainder would be a constant.) Let the quotient be $a\,x^2 + b\, x + c$ with coefficients $a$ , $b$ , and $c$ .

$4x^3 + 2x + 7 = \left(a\,x^2 + b\, x + c\right)(x + 3)$ .

Start by finding the first coefficient of the quotient.

The degree-three term on the left-hand side is $4 x^3$ . On the right-hand side, that would be $a\, x^3$ . Hence $a = 4$ .

Now, given that $a = 4$ , rewrite the right-hand side:

$\begin{aligned}&\left(4\,x^2 + b\, x + c\right)(x + 3) \cr =& \left(4x^2 + (b\, x + c)\right)(x + 3) \cr =& 4x^2(x + 3) + (bx + c)(x + 3) \cr =& 4x^3 + 12x^2 + (bx + c)(x + 3)\end{aligned}$ .

Hence:

$4x^3 + 2x + 7 = 4x^3 + 12x^2 + (b\,x + c)(x + 3)$

Subtract $\left(4x^3 + 12x^2\right$ from both sides of the equation:

$-12x^2 + 2x + 7 = (b\,x + c)(x + 3)$ .

The term with a degree of two on the left-hand side has coefficient $(-12)$ . Since the only term on the right hand side with degree two would have coefficient $b$ , $b = -12$ .

Again, rewrite the right-hand side:

$\begin{aligned}&\left(-12 x + c\right)(x + 3) \cr =& \left(-12 x+ c\right)(x + 3) \cr =& (-12x)(x + 3) + c(x + 3) \cr =& -12x^2 -36x + (bx + c)(x + 3)\end{aligned}$ .

Subtract $-12x^2 -36x$ from both sides of the equation:

$38x + 7 = c(x + 3)$ .

By the same logic, $c = 38$ .

Hence the quotient would be $(4x^2 - 12x + 38)$ .

6 0

3 years ago

The stopping distance, D, in feet of a car is directly proportional to the square of it's speed, V. Write the direct variation e

kow [346]

Answer:

$D=kV^2$

Step-by-step explanation:

In this problem, it is given that,

The stopping distance, D, in feet of a car is directly proportional to the square of it's speed, V.

We need to write the direct variation equation for the scenario above. It can be given by :

$D\propto V^2$

To remove the constant of proportionality, we put k.

$D=kV^2$

k is any constant

Hence, this is the required solution.

4 0

2 years ago

A quadrilateral is located on the coordinate plane with vertices at (2, 6), (2, −2), (4, −2), and (4, 6). Choose the vertices of

AURORKA [14]

Check the picture below.

5 0

2 years ago

What number complete the fallowing equation? 8×(40+7)=(8×_)+(8×7) A=40 B=47 C=320 D =376

11Alexandr11 [23.1K]

8x40=320 (+) 8x7=56 (=) 376.

A=40

hope this helped

3 0

3 years ago

Read 2 more answers

Ahhhh i need help again.

qwelly [4]

Answer:

B

Step-by-step explanation:

A. these simply to 21 + 7x and 21 + 3x

this one is incorrect because the 7x and 3x are different

B. these simplify to 10 + x and 10 + x

this is the correct one since they are exactly the same

C. these simplify to 21x and 7x + 21

these two are not the same because one expression has only a number with a variable but the other one has a number with a variable <em>and </em>another number

D. these simplify to $\frac{7}{3-x}$ and $\frac{7}{x-3}$

in subtraction, the order of the 3 and the x matters, so the equations are not the same
example: 6 - 4 = 2 but 4 - 6 = -2

3 0

2 years ago