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Kisachek [45]
3 years ago
6

A balloon rising at a constant rate will rise farther in 60 seconds than in 45 seconds. Which inequality shows this in function

notation?
Mathematics
1 answer:
Citrus2011 [14]3 years ago
8 0
Call f(t) the function that gives the rise of the balloon; then the statment translate to:

f(60) > f(45)
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Find the slope of line that is parallel to -2x=3y+5
In-s [12.5K]

Answer: m = -\frac{2}{3}

Step-by-step explanation:

Turn the equation into slope-intercept form: -3y = 2x + 5

Reduce: y = -\frac{2}{3}x -\frac{5}{3}

Your parallel slope is: -\frac{2}{3}

7 0
2 years ago
g Annual starting salaries in a certain region of the U. S. for college graduates with an engineering major are normally distrib
algol13

Answer:

The probability that the sample mean would be at least $39000 is of 0.8665 = 86.65%.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean $39725 and standard deviation $7320.

This means that \mu = 39725, \sigma = 7320

Sample of 125

This means that n = 125, s = \frac{7320}{\sqrt{125}}

The probability that the sample mean would be at least $39000 is about?

This is 1 subtracted by the pvalue of Z when X = 39000. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{39000 - 39725}{\frac{7320}{\sqrt{125}}}

Z = -1.11

Z = -1.11 has a pvalue of 0.1335

1 - 0.1335 = 0.8665

The probability that the sample mean would be at least $39000 is of 0.8665 = 86.65%.

4 0
2 years ago
What is the coefficient of q in the sum of these two expressions?
a_sh-v [17]

Answer: 1/2

Step-by-step explanation:

3 0
3 years ago
Somebody please help it would be much appreciated.
Sav [38]

Answer:

25

Step-by-step explanation:

as you can see test a is further away from the ruler you have to put it at 0 so that you can get your answer I am not sure if it's correct or not

7 0
2 years ago
Read 2 more answers
the rain gauge shows 3 centimeters of water which equation gives height h it rains at a rate of 0.25 centimeters per hour after
Vilka [71]
0.25t = 3 is the equation or 0.25t = h but the first one would be used to solve it i think 
8 0
3 years ago
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