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Anon25 [30]
1 year ago
14

Find the area the sector.arc circle 7A. 1083π4 in²B. 1083π8 in²C. 57π4 in²D. 38π in²

Mathematics
1 answer:
Allisa [31]1 year ago
7 0

Solution:

Given:

A circle with the sector details;

\begin{gathered} r=19\text{ }in \\ \theta=135^0 \end{gathered}

The area of a sector is given by;

\begin{gathered} A=\frac{\theta}{360}\times\pi r^2 \\ A=\frac{135}{360}\times\pi\times19^2 \\ A=\frac{1083\pi}{8}\text{ }in^2 \end{gathered}

Therefore, the area of the sector is;

\frac{1083\pi}{8}\text{ }in^2

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Answer:

$3,078.04

Step-by-step explanation:

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3 years ago
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Step-by-step explanation:

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Find the period of the function. y=3 sin x/8
Alexus [3.1K]

Answer:

The period of given function is  Period = 16\pi

So, Option B is correct.

Step-by-step explanation:

In this question we need to find the period of the function y= 3 sin x/8

The formula used to find period of function is: \frac{2\pi }{b}

We need to know the value of b.

To find the value of b we compare the standard equation with the equation of function given.

Standard Equation: y = a sin(bx - c) +d

Given Equation: y= 3 sin(x/8)

Comparing we get:

a= 3

b= 1/8

c= 0

d=0

So, we get the value of b i.e 1/8. Putting it in the formula to find period of given function.

Period = \frac{2\pi }{b}

Period = \frac{2\pi }{\frac{1}{8}}

Solving,

Period = 2\pi *8

Period = 16\pi

So, the period of given function is  Period = 16\pi

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