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3 years ago

Can someone please help me factor 6x^2 - 9x+42

Mathematics

2 answers:

nordsb [41]3 years ago

7 0

Answer:

-3(x-2)(2x+7)

Step-by-step explanation:

frutty [35]3 years ago

6 0

Answer:

3(2x^2-3x+14)

Step-by-step explanation:

6x^2-9x+42

All three terms have a common factor of 3

3(2x^2-3x+14)

Now let's focus on 2x^2-3x+14 and bring down the factor 3 later

so a=2

b=-3

c=14

Let's try to find two factors for ac that multiply to be a*c and add up to be b.

ac=28

b=-3

-----

ac=7(4)=14(2)=8(2)

Even if I made these pairs with both negatives nothing would give me -3

So you can only go as far as 3(2x^2-3x+14)

Here is another thing to help you if you have ax^2+bx+c and b^2-4ac<0 then it can't be factored (over reals)

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Step-by-step explanation:

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3 years ago

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Natasha_Volkova [10]

Answer:

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Step-by-step explanation:

First, you multiply 3x and 8 to equal 24x²
Then, you find the variables that equal -10x (-2x, and -12x)
then replace the -10x with the two variables you found (3x²-2x-12x+8)
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