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3 years ago

Solve systems of three variable equations - how to do :(

Mathematics

1 answer:

krek1111 [17]3 years ago

7 0

a= 6-2b-3c

then put that equation inside the first one and then the second one

you get -6*(6-2b-3c)+2b-3c=23

and 5*(6-2b-3c)+4b-3c=-12

14b-15c=59

14b-18c=18/*(-1)

--------------------

3b=41

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Write 6.92 x 10 (-8 exponent) in standard notation.. A. 0.00000692 . B. 0.000000692 . C. 0.0000000069 . D. 0.0000000692

Fofino [41]

OPTION D IS YOUR ANSWER.......

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3 years ago

What would be the answer?

iVinArrow [24]

Answer:

answer is C

Step-by-step explanation:

because -1<5

and not 6<-1 or -5>5

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3 years ago

the number of students in a chess club decreased from 37 to 19. What is the percent decrease? Round your answer to the nearest p

Tema [17]

Answer:

You should be able to get your answer by

Step-by-step explanation:

For example let's sayAbout 33%. You divide 12 by 18 and get 0.6666666 and it goes on. So, rounded to the nearest percent, it is 67%. Then, you subtract it from 100 and get 33%. So the percent decrease is 33%.

Hope this helps

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2 years ago

There are 7 boxes stacked on the floor in the math department supply closet. Each box has a height of 10 inches or 8 inches. The

Orlov [11]

Answer:

5 of the 7 boxes are 8 inches in height

Step-by-step explanation:

Mathematically;

1 ft = 12 inches

So, 5 ft will measure 5 * 12 = 60 inches

So from what we have ,

We want to combine 8 and 10 inches to give 60 inches total

Let the number of 10 inches be x and the number of 8 inches be y

Mathematically;

x + y = 7 •••••(i)

10x + 8y = 60 ••••(ii)

From equation i, x = 7-y

Put this in equation ii

10(7-y) + 8y = 60

70-10y + 8y = 60

70-60 = 10y-8y

2y = 10

y = 10/2

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3 years ago

A computer can be classified as either cutting dash edge or ancient. Suppose that 94% of computers are classified as ancient.

taurus [48]

Answer:

(a) 0.8836

(b) 0.6096

(c) 0.3904

Step-by-step explanation:

We are given that a computer can be classified as either cutting dash edge or ancient. Suppose that 94% of computers are classified as ancient.

(a) Two computers are chosen at random.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 2 computers

r = number of success = both 2

p = probability of success which in our question is % of computers

that are classified as ancient, i.e; 0.94

LET X = Number of computers that are classified as ancient

So, it means X ~ $Binom(n=2, p=0.94)$

Now, Probability that both computers are ancient is given by = P(X = 2)

P(X = 2) = $\binom{2}{2}\times 0.94^{2} \times (1-0.94)^{2-2}$

= $1 \times 0.94^{2} \times 1$

= 0.8836

(b) Eight computers are chosen at random.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 8 computers

r = number of success = all 8

p = probability of success which in our question is % of computers

that are classified as ancient, i.e; 0.94

LET X = Number of computers that are classified as ancient

So, it means X ~ $Binom(n=8, p=0.94)$

Now, Probability that all eight computers are ancient is given by = P(X = 8)

P(X = 8) = $\binom{8}{8}\times 0.94^{8} \times (1-0.94)^{8-8}$

= $1 \times 0.94^{8} \times 1$

= 0.6096

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 8 computers

r = number of success = at least one

p = probability of success which is now the % of computers

that are classified as cutting dash edge, i.e; p = (1 - 0.94) = 0.06

LET X = Number of computers classified as cutting dash edge

So, it means X ~ $Binom(n=8, p=0.06)$

Now, Probability that at least one of eight randomly selected computers is cutting dash edge is given by = P(X $\geq$ 1)

P(X $\geq$ 1) = 1 - P(X = 0)

= $1 - \binom{8}{0}\times 0.06^{0} \times (1-0.06)^{8-0}$

= $1 - [1 \times 1 \times 0.94^{8}]$

= 1 - $0.94^{8}$ = 0.3904

Here, the probability that at least one of eight randomly selected computers is cutting dash edge is 0.3904 or 39.04%.

For any event to be unusual it's probability is very less such that of less than 5%. Since here the probability is 39.04% which is way higher than 5%.

So, it is not unusual that at least one of eight randomly selected computers is cutting dash edge.

7 0

2 years ago

Solve systems of three variable equations - how to do :(​

Solve systems of three variable equations - how to do :(