2 years ago

Solve systems of three variable equations - how to do :(

Mathematics

1 answer:

krek1111 [17]2 years ago

7 0

a= 6-2b-3c

then put that equation inside the first one and then the second one

you get -6*(6-2b-3c)+2b-3c=23

and 5*(6-2b-3c)+4b-3c=-12

14b-15c=59

14b-18c=18/*(-1)

--------------------

3b=41

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2 years ago

Read 2 more answers

How do i do 13 A and 13 C

Paladinen [302]

$\bf c^2=a^2+b^2\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\ side\\
b=opposite\ side\\
-------------\\
\textit{since they're equal}\\
\textit{let's call them "u"}\\
a=u\qquad since\qquad a=b\\
b=u\\
--------\\

c=850
\end{cases}
\\ \quad \\
850^2=u^2+u^2\implies 850^2=2u^2\implies \cfrac{850^2}{2}=u^2
\\ \quad \\
\sqrt{\cfrac{850^2}{2}}=u\implies 
\begin{cases}
\sqrt{\cfrac{850^2}{2}}=a\\\\
\sqrt{\cfrac{850^2}{2}}=b
\end{cases}$

now, for 13c
how much square feet will be covered? square feet means, Area,
namely, what is the area of that triangle?

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3 years ago

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Reptile [31]

Answer:

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Step-by-step explanation:

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3 years ago

Solve systems of three variable equations - how to do :(​

Solve systems of three variable equations - how to do :(