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lyudmila [28]
4 years ago
5

Can someone explain the meaning of the Spiral of Theodorus?

Mathematics
1 answer:
drek231 [11]4 years ago
8 0

Answer:

The Spiral of Theodorus is a construction of continuous right triangles, and each triangle has a side length of one representing the of the Pythagorean theorem, with the other sides filling in the spaces for the and in the theorem. hope that helped :)

Step-by-step explanation:

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Can someone please help me on this
ohaa [14]

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the 1 one

Step-by-step explanation:

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Viefleur [7K]

Answer:

2625 cubic meters

Step-by-step explanation:

the volume of a rectangle is V = length x width x height (depth in this case)

so, 50m x 30m x 1.75m = 2625m^3

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Rewrite in simplest rational exponent form √x • 4√x. Show each step of your process.
Studentka2010 [4]
I like to think of radicals (or square roots) just as x terms-
here, we have the equivalent (kind of) to x * 4x. 
Since these are both x terms and 4x= x*x*x*x, we can simply write 5x.

Im not sure what your teacher is asking you to communicate, but most simply would like to see evidence that you understand the material rather than simply looking up the answer... (i mean without reading an explanation xD)
4√x= √x*√x*√x*√xso √x • 4√x =5√x
5 0
3 years ago
The diameter of a circle measures 10 yd. What is the circumference of the circle?
crimeas [40]

Answer:

31.4 yards

Step-by-step explanation:

Radius (R) = d / 2

R = 10 / 2 = 5 yards

Circumference (C) = 2 π r

C = 2 * 3.14 * 5 yards

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3 0
4 years ago
Evaluate the given integral by changing to polar coordinates. 8xy dA D , where D is the disk with center the origin and radius 9
BabaBlast [244]

Answer:

0

Step-by-step explanation:

∫∫8xydA

converting to polar coordinates, x = rcosθ and y = rsinθ and dA = rdrdθ.

So,

∫∫8xydA = ∫∫8(rcosθ)(rsinθ)rdrdθ = ∫∫8r²(cosθsinθ)rdrdθ = ∫∫8r³(cosθsinθ)drdθ

So we integrate r from 0 to 9 and θ from 0 to 2π.

∫∫8r³(cosθsinθ)drdθ = 8∫[∫r³dr](cosθsinθ)dθ

= 8∫[r⁴/4]₀⁹(cosθsinθ)dθ

= 8∫[9⁴/4 - 0⁴/4](cosθsinθ)dθ

= 8[6561/4]∫(cosθsinθ)dθ

= 13122∫(cosθsinθ)dθ

Since sin2θ = 2sinθcosθ, sinθcosθ = (sin2θ)/2

Substituting this we have

13122∫(cosθsinθ)dθ = 13122∫(1/2)(sin2θ)dθ

= 13122/2[-cos2θ]/2 from 0 to 2π

13122/2[-cos2θ]/2 = 13122/4[-cos2(2π) - cos2(0)]

= -13122/4[cos4π - cos(0)]

= -13122/4[1 - 1]

= -13122/4 × 0

= 0

5 0
3 years ago
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