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Xelga [282]
3 years ago
7

How is the formula for the area of a triangle related to the formula for the area of a parallelogram?

Mathematics
1 answer:
Andreas93 [3]3 years ago
7 0
Area of a triangle is A= 1/2 b x h and Area of a parallelogram is A=b x h. So I would say the area of a triangle is half of the area of a parallelogram. Or a parallelogram is double the area of a triangle.
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A polynomial function has a root of -4 with multiplicity of 4, a root of -1 with multiplicity of 3, and a root of 5 with multipl
Dmitrij [34]

Answer:

To draw this graph, we start from the left in quadrant 3 drawing the curve to -4 on the x-axis to touch it but not cross. We continue back down and curve back around to cross the x-axis at -1. We continue up past -1 and curve back down to 5 on the x-axis. We touch here without crossing and draw the rest of our function heading back up. It should form a sideways s shape.


Step-by-step explanation:


A polynomials is an equation with many terms whose leading term is the highest exponent known as degree. The degree or exponent tells how many roots exist. These roots are the x-intercepts.


This polynomial has roots -4, -1, and 5. This means the graph must touch or cross through the x-axis at these x-values. What determines if it crosses the x-axis or the simple touch it and bounce back? The even or odd multiplicity - how many times the root occurs.


In this polynomial:


Root -4 has even multiplicity of 4 so it only touches and does not cross through.


Root -1 has odd multiplicity of 3 so crosses through.


Root 5 has even multiplicity of 6 so it only touches and does not cross through.


Lastly, what determines the facing of the graph (up or down) is the leading coefficient. If positive, the graph ends point up. If negative, the graph ends point down. All even degree graphs will have this shape.


To draw this graph, we start from the left in quadrant 3 drawing the curve to -4 on the x-axis to touch it but not cross. We continue back down and curve back around to cross the x-axis at -1. We continue up past -1 and curve back down to 5 on the x-axis. We touch here without crossing and draw the rest of our function heading back up. It should form a sideways s shape.

7 0
3 years ago
Read 2 more answers
Answer this please help needed
klasskru [66]

3.√(27x^9) = (27x^9)^(1/3) = 3x^3

8 0
3 years ago
The length of the rectangle is 3 cm and the width is 5 cm what will the area be?
WINSTONCH [101]

Answer:

15 cm²

Step-by-step explanation:

3(5)=15 cm²

3 0
2 years ago
The volume of an oblique pyramid with a square base is V units3 and the height is h units. Which expression represents the area
givi [52]

Answer:

Area of the base of the pyramid = V/h

Step-by-step explanation:

Mathematically, we know that the volume of the pyramid can be calculated by multiplying the area of the base by the height of the pyramid

Now using the variables in the question;

V = area of base * height of pyramid

Area of base = V/height of pyramid

Area of base = V/h

3 1
3 years ago
Please give an explanation on how you got this answerI'm not sure if it's too late or what, but I can't get it.
Alona [7]
Step 1: multiple the second equation by 2 so that you get -1/4 for the coefficient of y, the same as in equation 1
equation 2 multiply by 2: 1/4 x - 1/4 y=38  ..........name this equation 3
subtract equation 1 from equation 3: (1/4 x -1/2 x)=38-10
-1/4 x = 28
x=-112
plug in x=-112 in any of the equation, you will get y=-264
so the answer is A
8 0
2 years ago
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