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PSYCHO15rus [73]
3 years ago
10

What is the value of 4⋅(2^2+5)^2÷3−1?

Mathematics
1 answer:
mel-nik [20]3 years ago
5 0

Hi there!

<u>Here is the step by step explanation into solving this :</u>

4 × (2² + 5)² ÷ 3 - 1

Start by solving the inside of the parentheses

2² = 2 × 2 = 4

4 + 5 = 9

Distribute the "²" to the whole parentheses

9² = 9 × 9 = 81


4 × 81 ÷ 3 - 1

Do the multiplication, then the division and lastly the subtraction

4 × 81 = 324

324 ÷ 3 = 108

108 - 1 = 107


The answer is : 107


There you go! I really hope this helped, if there's anything just let me know! :)

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2. A chemist has a 25% and a 50% acid solution. How
AnnZ [28]

Answer:

x is mL of 25% acid and y is mL of 50% acid

We set up 2 equations:

A) x + y = 250

B) .25 x + .50y = .35 * 250 which equals

B) .25x + .50y = 87.50  Multiplying A) by -.5

A) -.5x -.5y = -125  adding the equations we get

-.25x = -37.50

x = 150 mL

y = 100 mL

Source:  http://www.1728.org/mixture.htm

Step-by-step explanation:

7 0
3 years ago
What is the value of the problem below?
Hitman42 [59]

Answer:

90

Step-by-step explanation:

The first term  = 6* 2^0 =  6

The second term = 6 * 2^ (2-1) = 6*2 = 12

The third term = 6* 2^(3-1) = 6*2^2 = 6*4 = 24

The fourth term = 6* 2^(4-1) = 6* 2^3 = 6*8 = 48

S4  is the sum of the 1st four terms

S4 = 6+ 12+24+ 48 = 90

7 0
2 years ago
10 POINTS PLEASE HELP !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
loris [4]
I think its -44+9i if i am not right i am so sorry<span>
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8 0
3 years ago
Read 2 more answers
Howdoyouwrite 2/4 as a percentage? write your answer using a percent sign %?
xz_007 [3.2K]
First, divide 2 by 4 which = 0.5
Next, move the decimal point two places over to make 0.5 = 50.0
Then, take 50.0 and add the % sign. This would make = 50%
I hope this helped! 
4 0
3 years ago
the value of c guaranteed to exist by the Mean Value Theorem for V(x) = x² in the interval [0, 3] is...? a) 1 b) 2 c) 3/2 d) 1/2
lilavasa [31]

Answer:  c) \dfrac{3}{2} .

Step-by-step explanation:

Mean value theorem : If f(x) is defined and continuous on the interval [a,b] and differentiable on (a,b), then there is at least one number c in the interval (a,b) (that is a < c < b) such that

\begin{displaymath}f'(c) = \frac{f(b) - f(a)}{b-a} \cdot\end{displaymath}

Given function : f(x) = x^2

Interval : [0,3]

Then, by the mean value theorem, there is at least one number c in the interval (0,3) such that

f'(c)=\dfrac{f(3)-f(0)}{3-0}\\\\=\dfrac{3^2-0^2}{3}=\dfrac{9}{3}\\\\=3

\Rightarrow\ f'(c)=3\ \ \ ...(i)

Since f'(x)=2x

then, at x=c, f'(c)=2c\ \ \ ...(ii)

From (i) and (ii), we have

2c=3\\\\\Rightarrow\ c=\dfrac{3}{2}

Hence, the correct option is c) \dfrac{3}{2} .

4 0
3 years ago
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