Ask question

Ask question

All categories

3 years ago

8

A random two digit number (10-99) is drawn. Find P(odd number)

1 answer:

Mars2501 [29]3 years ago

8 0

Answer:

P(odd number) = 0.5

Step-by-step explanation:

There are 90 members in the set (10, 11, 12, .. , 97, 98, 99)

When we have an even number of consecutive numbers, the number of even numbers equals the number of odd numbers. This means that half of the numbers in this set are even and half of them are odd.

So the probability of P(odd number) = 0.5

You might be interested in

Solve For L: A = L ⋅ W ⋅ H<br><br> L=aw/h<br><br> L=wh/a<br><br> L=a/wh<br><br> L=w/ha

bonufazy [111]

Ok so what you're trying to do is get L by itself so to do this you move everything to the other side:
A=L*WH
$\frac{A}{WH}$ =L
So you answer would be: C

8 0

3 years ago

Read 2 more answers

A rental car company charges $40.18 per day to rent a car and $0.05 for every mile driven. Jacob wants to rent a car, knowing th

Harlamova29_29 [7]

Answer:

b) 270 ≥ 40.18d + 3.75

Step-by-step explanation:

Per day is a variable, so it's 40.18d

Per mile is also a variable so 0.05m

40.18d + 0.05m ≤ 270

40.18d + 0.05(75) ≤ 270

40.18d + 3.75 ≤ 270

5 0

3 years ago

Wilma bought a skateboard for 20% off. The normal price was 120.90. How much did Wilma pay for the skateboard, not including tax

evablogger [386]

The answer is 96.72

7 0

3 years ago

18 students at woodworth school. 1/2 as many girls as boys. how many girls

Ganezh [65]

9 girls and 9 boys equals 18 students

8 0

4 years ago

Read 2 more answers

A football player kicks a ball with an initial upward velocity of 47 ft./s. The initial height of the ball is 3 feet. The functi

Rashid [163]

Answer: 3 seconds

We are given the following function:

$h(t)=-16{t}^{2}+V.t+h(o)$ (1)

Where:

$t$ is the time the ball is in the air

$V=47ft/s$ the initial upward velocity

$h(o)=3ft$ the initial height of the ball

$h(t)$ is the final height of the ball. If no one catches it, this will be <u>zero</u>

So, equation (1) changes to:

$-16{t}^{2}+V.t+h(o)=0$ (2)

Substituting the known values:

$-16{t}^{2}+(47ft/s).t+3ft=0$ (3)

This is a quadratic equation in the form $a{t}^{2}+b.t+c=0$ . In order to find $t$ we can use the quadratic formula for the roots:

$t=\frac{-b\pm\sqrt{-4ac}}{2a}$ (4)

Where $a=-16$ , $b=47$ and $c=3$

Substituting this values in (4):

$t=\frac{-47\pm\sqrt{-4(-16)(3)}}{2(-16)}$ (5)

$t=\frac{-47\pm\sqrt{2401}}{-32}$ (6)

$t=\frac{-47\pm\49}{-32}$ (7)

For $t1$ :

$t1=\frac{-47+49}{-32}=-0.0625 s$ (8)>>>> This result does not work for us because is negative

For $t2$ :

$t2=\frac{-47-49}{-32}=3 s$ (9)>>>This is the result

Therefore:

<h2> If no one catches the ball, it will be 3 s in the air</h2>

6 0

3 years ago