well, you already know an absolute value expression has a ± siblings, so let's proceed without much fuss.
![\bf |2x-5|=4\implies \begin{cases} +(2x-5)=4\implies 2x=9\implies x=\cfrac{9}{2}\\[-0.5em] \hrulefill\\ -(2x-5)=4\implies 2x-5=-4\\[1em] 2x=1\implies x=\cfrac{1}{2} \end{cases}](https://tex.z-dn.net/?f=%20%5Cbf%20%7C2x-5%7C%3D4%5Cimplies%20%20%5Cbegin%7Bcases%7D%20%2B%282x-5%29%3D4%5Cimplies%202x%3D9%5Cimplies%20x%3D%5Ccfrac%7B9%7D%7B2%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20-%282x-5%29%3D4%5Cimplies%202x-5%3D-4%5C%5C%5B1em%5D%202x%3D1%5Cimplies%20x%3D%5Ccfrac%7B1%7D%7B2%7D%20%5Cend%7Bcases%7D%20)
Answer: y=17-5x/-9
Step-by-step explanation: 5x-9y=17
-9y=17-5x
Y=17-5x/-9
You can’t go any further than that because you can’t combine unlike Terms on the right side of the equation.
0.057x 10 is equal to .57. All you have to do is move the decimal to the right one time because there is one zero in 10.
Reflecting the polygon FGHI across the line involves flipping the line across the line y = -1
<h3>How to reflect the polygon?</h3>
The coordinates are given as:
F(2, – 1), G(5,2), H(8, 3), and I(6, 0)
The line of reflection is given as:
y = -1
To reflect the line, we apply the following rule of reflection
(x,y)
(x,-y-2)
So, we have the following coordinates of the image
F' = (2, – 1)
G' = (5,-4)
H' = (8, -5)
I' = (6, -2)
See attachment for the image of the reflected polygon
Read more about reflection at:
brainly.com/question/4289712