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Savatey [412]
4 years ago
11

What is the equation of a vertical line passing through the point (-5,-1)

Mathematics
1 answer:
Stels [109]4 years ago
8 0
Learn this :
VUX -- vertical line, undefined slope, represented by x = a number
HOY -- horizontal line, 0 slope, represented by y = a number

ok....so u need the equation for a vertical line passing thru (-5,-1)...
a vertical line is represented by x = a number.....and that number will be the x value of ur points.

Therefore, ur equation is : x = -5 <==

**just so u know, if u were needing a horizontal line going thru the same points, ...and a horizontal line is represented by y = a number...with the number being the y value of ur points....the equation would be y = -1


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Dafna11 [192]
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6 0
3 years ago
How do u do this.I need major help on it
Tpy6a [65]
Look for what 'y' is when t = 1 and t = 2. Go to the graph, look at 1 on the bottom axis and go up till you find the point, then go all the way to the left to see what the y-value is, in this case it should be 1200. If you do the same with t = 2, you will get 2400. So our two ordered pairs are:

(1, 1200), (2, 2400)

We can find the slope of these two points by plugging them into the slope formula:

\sf m=\dfrac{y_2-y_1}{x_2-x_1}

For points in the form of (x1, y1), (x2, y2). Plug in what we know:

\sf m=\dfrac{2400-1200}{2-1}

Subtract:

\sf m=\dfrac{1200}{1}

Divide:

\sf m=1200

This is the slope, so we can write the equation:

\boxed{\sf y=1200t}
4 0
3 years ago
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