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Alekssandra [29.7K]
4 years ago
5

Jeremy walks into a video arcade with a pocketful of quarters. He spends them at a rate of four every quarter hour until he runs

out. If the amount of of quarters Jeremy has is graphed overtime, which feature of the graph corresponds to Jeremy's initial amount of quarters, before he spends the first one ?
Answer Choices :
A. The y-intercept
B. The slope
C. The x-intercept
D. The minimum value
Mathematics
2 answers:
sdas [7]4 years ago
5 0
The answer is A as he has all of the quarters when he spends no time in the arcade
goldenfox [79]4 years ago
3 0

Answer: A. The y-intercept

Step-by-step explanation:

Given : The amount of quarters Jeremy has is graphed overtime.

Usually we represent the independent variable (time) by x and dependent variable (quarters) by y.

The y-intercept is the point in the graph where the x coordinate is zero.

When x-coordinate is zero then the graph is representing the initial value.

Hence, the feature of the graph corresponds to Jeremy's initial amount of quarters, before he spends the first one is the y-intercept .

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If they are Similar what’s is the similarity statement ?
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Show the whole pic

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6 0
3 years ago
22: A 2.0 kg object moves along the x-axis under the influence of an unknown force. Its potential energy due to the force is U(x
aleksandr82 [10.1K]

Answer: a) -13.25 N, b) 1.78 m/sec

Step-by-step explanation:

Since we have given that

U(x)=ax^4+bx^2

where

a=2.5\ J/m^4\\\\b=12\ J/m^2

As we know that

F=\dfrac{-dU}{dx}=-(4ax^3+2bx)

Here, x= 0.5 m

So, it becomes,

F=-(4\times 2.5\times (0.5)^3+2\times 12\times 0.5)=-13.25\ N

Now, we need to find the velocity when it crosses the origin,

F=mg\\\\F=m\dfrac{dv}{dt}\\\\F=mv\dfrac{dv}{dx}\\\\-(4ax^3+2bx)dx=mvdv\\\\\int\limits^{0.5}_0 {-(4ax^3+2bx)} \, dx =\int\limits {mv} \, dv\\\\ \dfrac{-4ax^4}{4}+\dfrac{2bx^2}{2}|_0^{0.5}=\dfrac{mv^2}{2}\\\\ax^4+bx^2|_0^{0.5}=\dfrac{mv^2}{2}\\\\2.5(0.5)^4+12(0.5)^2=\dfrac{2v^2}{2}\\\\0.15625+3=v^2\\\\3.15625=v^2\\\\\sqrt{3.15625}=v\\\\v=1.78

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7 0
4 years ago
Put these over a common denominator: ³/5 and 4/7
Anastaziya [24]

ANSWER 35

Step-by-step explanation:

7 and 5 - 35

Now just simplify the 3 and 4 :)

6 0
3 years ago
A park district has 45 pine trees and 30 oak trees to be planted. They are separating the trees for different areas. They want e
Lady_Fox [76]

Answer:

greatest number of areas that can be created=5

Step-by-step explanation:

given data

Number of pine trees = 45

Number of oak trees = 30

solution

we want area have same number of both trees

so we get here greatest number of area

we find here  greatest common factor of 45 and 30

so Prime factorization of 45 and 30 are

45 = 3 × 3 ×  5

30 = 2 × 3 ×  5

as here GCF = 5

so here greatest number of areas that can be created=5

6 0
3 years ago
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