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GrogVix [38]
3 years ago
9

write a rule to represent the relationship between the number of typed words and the time in which they are typed​

Mathematics
1 answer:
liberstina [14]3 years ago
4 0
It depends on the speed of typing. Multiply the speed by the time.
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For the function f(x)=x^2, what effect will multiplying f(x) by 1/2 have on the graph?
erma4kov [3.2K]
For the function f ( x ) = x² we have the new function f 1 ( x ) = 1/2 x².
f ( x ) = a · x²
- If |a| < 1   the graph is compressed vertically by a factor of a.
- If |a| > 1  the graph is stretched vertically by a factor of a.
Here:  a = 1/2 < 1
Answer:
C. The graph will be compressed vertically.
5 0
3 years ago
Find the slope of the proportional graph below.
In-s [12.5K]

Answer:

slope = 1

m = 1

Step-by-step explanation:

We count rise over run = 1/1

m = 1

y = x

5 0
3 years ago
Read 2 more answers
PLEASE HELP WILL MARK AS BRAINLIEST IF YOU ANSWER FIRST!!!!!!
vampirchik [111]
A + C
(-5, -7) is 7 units to the left of point H
(-7, 7) is more than 7 units up and left of point H
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4 0
3 years ago
Show that (x+1) is a factor of f(x)=19x^42+18x-1
Dmitry_Shevchenko [17]

Answer:

see explanation

Step-by-step explanation:

If (x + 1) is a factor then f(- 1) = 0

f(- 1) = 19(-1)^{42} + 18(- 1) - 1 = 19 - 18 - 1 = 0

Thus (x + 1) is a factor of f(x)

6 0
3 years ago
PLZ HURRY IT'S URGENT!!
Jet001 [13]

Answer:

OPTION C: 60%

Step-by-step explanation:

Chances of raining the next day + Chances that it will not rain = 100%

One of them should definitely be true.

So, if the chance of it raining tomorrow is 40% then there is 60% chance that it will not rain tomorrow.

This can also seen as follows:

Probability of rain tomorrow + Probability of no rain = 1

Given Probability of rain tomorrow = 40% = $ \frac{40}{100} = \frac{2}{5} $

Probability of no rain tomorrow = 1 - Probability of rain tomorrow

⇒ Probability of no rain = 1 - $ \frac{2}{5} $

⇒ Probability of no rain = $ \frac{3}{5} $

Expressing it as percentage: $ \frac{3}{5} \times 100 $ = 60%.

8 0
3 years ago
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