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lozanna [386]
3 years ago
9

Nevermind, the question has been solved.

Mathematics
2 answers:
san4es73 [151]3 years ago
7 0

okay.... I guess??? lol

Oksi-84 [34.3K]3 years ago
3 0

Answer:

Step-by-step explanation:

than im getting points ;)

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NO LINKS!!! What is the transformation f(x)= x^3:
Mama L [17]

Answer:

4.  Horizontal shrink by a factor of ¹/₅

5.  Left 5, Up 5

6.  Right 5, Down 5

Step-by-step explanation:

Transformations of Graphs (functions) is the process by which a function is moved or resized to produce a variation of the original (parent) function.

<u>Transformations</u>

For a > 0

f(x+a) \implies f(x) \: \textsf{translated}\:a\:\textsf{units left}

f(x-a) \implies f(x) \: \textsf{translated}\:a\:\textsf{units right}

f(x)+a \implies f(x) \: \textsf{translated}\:a\:\textsf{units up}

f(x)-a \implies f(x) \: \textsf{translated}\:a\:\textsf{units down}

y=a\:f(x) \implies f(x) \: \textsf{stretched parallel to the y-axis (vertically) by a factor of}\:a

y=f(ax) \implies f(x) \: \textsf{stretched parallel to the x-axis (horizontally) by a factor of} \: \dfrac{1}{a}

y=-f(x) \implies f(x) \: \textsf{reflected in the} \: x \textsf{-axis}

y=f(-x) \implies f(x) \: \textsf{reflected in the} \: y \textsf{-axis}

Identify the transformations that take the parent function to the given function.

<u>Question 4</u>

\textsf{Parent function}: \quad f(x)=x^3

\textsf{Given function}: \quad f(x)=(5x)^3

Comparing the parent function with the given function, we can see that the <u>x-value of the parent function</u> has been <u>multiplied</u> by 5.

Therefore, the transformation is:

y=f(5x) \implies f(x) \: \textsf{stretched parallel to the x-axis (horizontally) by a factor of} \: \dfrac{1}{5}

As a > 1, the transformation visually is a compression in the x-direction, so we can also say:  Horizontal shrink by a factor of ¹/₅

<u>Question 5</u>

\textsf{Parent function}: \quad f(x)=x^3

\textsf{Given function}: \quad f(x)=(x+5)^3+5

Comparing the parent function with the given function, we can see that there are a series of transformations:

<u>Step 1</u>

5 has been <u>added to the x-value</u> of the parent function.

f(x+5) \implies f(x) \: \textsf{translated}\:5\:\textsf{units left}

<u>Step 2</u>

5 has then been <u>added to function</u>.

f(x+5)+5 \implies f(x+5) \: \textsf{translated}\:5\:\textsf{units up}

<u>Transformation</u>:  Left 5, Up 5

<u>Question 6</u>

\textsf{Parent function}: \quad f(x)=x^3

\textsf{Given function}: \quad f(x)=(x-5)^3-5

Comparing the parent function with the given function, we can see that there are a series of transformations:

<u>Step 1</u>

5 has been <u>subtracted from the x-value</u> of the parent function.

f(x-5) \implies f(x) \: \textsf{translated}\:5\:\textsf{units right}

<u>Step 2</u>

5 has then been <u>subtracted from function</u>.

f(x-5)-5 \implies f(x-5) \: \textsf{translated}\:5\:\textsf{units down}

<u>Transformation</u>:  Right 5, Down 5

Learn more about graph transformations here:

brainly.com/question/27845947

6 0
2 years ago
Read 2 more answers
What is the distance between M(9, −5) and N(−11, 10)?
lesya692 [45]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{25 \: units}}}}}

Step-by-step explanation:

Let M ( 9 , -5 ) be ( x₁ , y₁ ) and N ( - 11 , 10 ) be ( x₂ , y₂ )

<u>Finding</u><u> </u><u>the </u><u>distance </u><u>between</u><u> </u><u>these</u><u> </u><u>points</u>

\boxed{ \sf{distance =  \sqrt{ {(x2 - x1)}^{2} +  {(y2 - y1)}^{2}  } }}

\longrightarrow{ \sf{ \sqrt{ {( - 11 - 9)}^{2}  +  {(10 - ( - 5))}^{2} } }}

\longrightarrow{ \sf{ \sqrt{ {( - 20)}^{2} +  {(10 + 5)}^{2}  } }}

\longrightarrow{ \sf{ \sqrt{ {( - 20)}^{2}  +  {(15)}^{2} } }}

\longrightarrow{ \sf{ \sqrt{400 + 225}}}

\longrightarrow{ \sf{ \sqrt{625}}}

\longrightarrow{ \sf{ \sqrt{ {(25)}^{2} } }}

\longrightarrow{ \sf{25 \: units}}

Hope I helped!

Best regards! :D

7 0
3 years ago
Will mark brainliest
faust18 [17]

x^3 is strictly increasing on [0, 5], so

\max\{x^3 \mid 0\le x\le5\} = 5^3 = 125

and

\min\{x^3 \mid 0 \le x\le5\} = 0^3 = 0

so the integral is bounded between

\displaystyle \boxed{0} \le \int_0^5x^3\,dx \le \boxed{125}

8 0
2 years ago
Can Someone Please Help Me With This Question. I'll post a picture of the question ​
Vedmedyk [2.9K]

Answer:

y-7=3(x-9)

Step-by-step explanation:

The form of equation of line given in the problem is the point-slope form of a line. That is given by:

y-y_1=m(x-x_1)

We need y_1 and m (denoted by boxes)

y_1 is the y coordinate of the first set of points.

The first coordinate pair is (9,7), so y_1  would be 7

y_1=7

Now, the slope (m).

It has formula

m=\frac{y_2-y_1}{x_2-x_1}

So, x_1 = 9

y_1 = 7

x_2 = 4

y_2 = -8

Substituting, we get the slope to be:

m=\frac{y_2-y_1}{x_2-x_1}\\m=\frac{-8-7}{4-9}\\m=\frac{-15}{-5}\\m=3

Hence, the equation of the line in point-slope is:

y-7=3(x-9)

5 0
3 years ago
Is it possible to have a rotation that starts and end in the same quadrant?
densk [106]

Yes and no. It depends on the situation and how you're asking

3 0
4 years ago
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