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3 years ago

A bus traveled south for 520 kilometers. The entire trip took 3 hours. Calculate the velocity.

Mathematics

1 answer:

In-s [12.5K]3 years ago

5 0

Answer:

A bus traveled south for 520 kilometers. The entire trip took 3 hours. Calculate the velocity.

Step-by-step explanation:

A bus traveled south for 520 kilometers. The entire trip took 3 hours. Calculate the velocity.

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Formula for the sum of angles of a triangle: A+B+C=180 degrees, for C

nevsk [136]

A + B + C = 180
<span>C = 180 - A - B </span>

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3 years ago

The graph below describes the journey of a train between two cities.

Veseljchak [2.6K]

Answer:

[A] Acceleration in first 15 min = 200 km/h²

[B] Distance between two cities = 125 km

[C] Average Speed of journey = 62.5 km/hr

Step-by-step explanation:

To Solve:

Acceleration in first 15 min

Distance between two cities

Average speed of journey

Solve:

[A] Work out the acceleration, in km/h?, in the first 15 mins.

Each horizontal block is 1/8 hr = 7.5 min

Each vertical block is 10 km/hr

Time Velocity km/hr

0 Min ( 0 hr) 0

15 Min (1/4 hr) 50

45 Min (3/4 hr) 50

60 MIn ( 1 hr) 100

90 Min ( 3/2 hr) 100

120 Min ( 2hr) 0

Acceleration in first 15 min (1/4 hr) = (50 - 0)/(1/4 - 0) = 50/(1/4)

= 200 km/h²

Hence, Answer for [A] = 200 km/h²

[B] Work out the distance between the two cities. $60 Velocity (in km/h)

= (1/2)(0 + 50)(1/4 - 0) + 50 * (3/4 - 1/4) + (1/2)(50 + 100)(1 - 3/4) + 100 * (3/2 - 1) + (1/2)(100 + 0)(2 - 3/2)

= 25/4 + 25 + 75/4 + 50 + 25

= 125

Distance between two cities = 125 km

[C] Work out the average speed of the train during 20 the journey.

Average Speed of journey = 125/2 = 62.5 km/hr

[RevyBreeze]

5 0

2 years ago

Find the missing lengths: LK=15 and KH=9, find KI and HI.

Luda [366]

Answer:

KI=11.25 and HI=6.75

Step-by-step explanation:

Consider the below figure attached with this question.

According to Pythagoras Theorem:

$base^2+perpendicular^2=hypotenuse^2$

Use Pythagoras in triangle HKL

$LH^2+KH^2=LK^2$

$(LH)^2+9^2=15^2$

$(LH)^2+81=225$

$(LH)^2=144$

Taking square root on both sides.

$LH=12$

Let length of HI be x.

LI = 12+x

Use Pythagoras theorem in ΔKLI,

$(KI)^2+15^2=(12+x)^2$

$(KI)^2+225=x^2+24x+144$

$(KI)^2=x^2+24x+144-225$

$(KI)^2=x^2+24x-81...(1)$

Use Pythagoras theorem in ΔHKI,

$(KI)^2=x^2+9^2$

$(KI)^2=x^2+81...(2)$

From (1) and (2) we get

$x^2+81=x^2+24x-81$

$24x=162$

$x=\dfrac{162}{24}=6.75$

Hence, the measure of HI is 6.75 units.

Substitute x=6.75 in equation (2).

$(KI)^2=(6.75)^2+81$

$(KI)^2=126.5625$

Taking square root on both sides.

$KI=\sqrt{126.5625}$

$KI=11.25$

Hence, the measure of KI is 11.25 units.

3 0

3 years ago

Solve 23 - Q >-3(2-6)

Korolek [52]

Answer:

q < 11

Step-by-step explanation:

Distribute the -3

23 - q > 12

Add q and subtract 12

q < 11

5 0

2 years ago

Read 2 more answers

Rearranging literal equations!! really confused ASAPplease

valina [46]

Answer:

b = $\frac{8a-55}{5-a}$

Step-by-step explanation:

To clear the radicals square both sides

$\frac{1}{6-a}$ = $\frac{8+b}{b-7}$ ( cross- multiply )

(6 - a)(8 + b) = b - 7 ← expand factors on left using FOIL

48 + 6b - 8a - ab = b - 7 ( subtract 48 from both sides )

6b - 8a - ab = b - 55 ( add 8a to both sides )

6b - ab = b - 55 + 8a ( subtract b from both sides )

6b - ab - b = 8a - 55, that is

5b - ab = 8a - 55 ← factor out b from each term on the left side )

b(5 - a) = 8a - 55 ← divide both sides by (5 - a)

b = $\frac{8a-55}{5-a}$

7 0

3 years ago