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8090 [49]
4 years ago
9

HELPLP PLEASEEEE, ILL GIVE BRAINLIEST AND 20 POINTS

Mathematics
1 answer:
n200080 [17]4 years ago
5 0

Answer: What is the question?

Step-by-step explanation:

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Please help asap 25 pts
irakobra [83]

In a function, each domain element can have at most one range element. So we'll have to remove one of the links from 3. Either one can be removed, since it is OK for two domain elements to map to the same range element (as is the case for 3->b and 4->b).


This is all very theoretical, but here is a real life example.

Take f(x) = x²

You probably know that both f(2) and f(-2) is 4.

There 2 and -2 are in the domain, 4 is in the range.

7 0
4 years ago
HELP ME !! AND EXPLAIN HOW YOU GOT IT.
alukav5142 [94]

Answer:

<5=39

Step-by-step explanation:

<2=48

<3=93

<2 and <4 are equal to each other because they are alternate interior angles

93+48=141

180-141=39

5 0
3 years ago
Read 2 more answers
Find the quotient and remainder of 452 divided by 8
Luda [366]
452÷8= 56.5
56 remainder 5
3 0
3 years ago
Question 5 (5 points)
Tpy6a [65]

Answer:

The solution of the system of equations is, (1,-1,2)

Step-by-step explanation:

Given system equation;

x + 5y - 3z = -10

-5x + 6y – 5z = -21

-x + 8y - 8z = -25

Matrix form is written as;

\left[\begin{array}{ccc}1&5&-3\\-5&6&-5\\-1&8&-8\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right] = \left[\begin{array}{ccc}-10\\-21\\-25\end{array}\right] \\\\\\det. = 1\left[\begin{array}{cc}\\6&-5\\8&-8\end{array}\right] -5\left[\begin{array}{cc}\\-5&-5\\-1&-8\end{array}\right] -3\left[\begin{array}{cc}\\-5&6\\-1&8\end{array}\right] \\\\\\det. = 1(-8) -5(35)-3(-34)= -8 - 175+ 102 = -81

Cofactor;

First \ row \left[\begin{array}{cc}+\\ 6&-5\\\ 8&-8\end{array}\right  \left\begin{array}{cc}-\\ -5&-5\\-1&-8\end{array}\right \left\begin{array}{cc}+\\-5&6\\-1&8\end{array}\right] = [-8  \ \ -35 \ \ -34]\\\\\\\ Second \ row \left[\begin{array}{cc}-\\ 5&-3\\\ 8&-8\end{array}\right  \left\begin{array}{cc}+\\ 1&-3\\-1&-8\end{array}\right \left\begin{array}{cc}-\\1&5\\-1&8\end{array}\right]  = [16\ \ -11 \ \ -13]\\\\\\

Third \ row \left[\begin{array}{cc}+\\ 5&-3\\\ 6&-5\end{array}\right  \left\begin{array}{cc}-\\ 1&-3\\-5&-5\end{array}\right \left\begin{array}{cc}+\\1&5\\-5&6\end{array}\right]= [-7 \  \ 20\ \ 31]

Cofactor = \left[\begin{array}{ccc}-8&-35&-34\\16&-11&-13\\-7&20&31\end{array}\right]

inverse \ matrix =-\frac{1}{81}  \left[\begin{array}{ccc}-8&16&-7\\-35&-11&20\\-34&-13&31\end{array}\right] \\\\\\

Solution of the matrix:

\left[\begin{array}{c}x\\y\\z\end{array}\right] = -\frac{1}{81}  \left[\begin{array}{ccc}-8&16&-7\\-35&-11&20\\-34&-13&31\end{array}\right]  X \left[\begin{array}{c}-10\\-21\\-25\end{array}\right] = \left[\begin{array}{c}\frac{-8*-10 }{-81 } +\frac{16*-21 }{-81 } + \frac{-7*-25 }{-81 }\\\\\frac{-35*-10 }{-81 } +\frac{-11*-21 }{-81 }+ \frac{20*-25 }{-81 }\\\\\frac{-34*-10 }{-81 }+ \frac{-13*-21 }{-81 }+ \frac{31*-25 }{-81 }\end{array}\right] \\\\\

\left[\begin{array}{c}x\\y\\z\end{array}\right] = \left[\begin{array}{c}\frac{-81}{-81} \\\\\frac{81}{-81} \\\\\frac{-162}{-81} \end{array}\right] =  \left[\begin{array}{c}1\\-1\\2\end{array}\right]

Therefore, the correct option is (1,-1,2)

5 0
3 years ago
Which fractions are equivalent to 3/4? check all tha apply.​
Alik [6]

Answer:

6/8, 9/12,  and 15/20

Step-by-step explanation:

just do 3 divided by 4 (3/4) and it equals 0.75 then do each and everyone like 6 divided by 8 (6/8) so it equals 0.75

7 0
3 years ago
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