Answer: y = 11/8 +7x/8
process: add 7x to both sides of the equation 8y=11+7x
Divide each term in 8y=11+7x by 8 and simplify
We're minimizing

subject to

. Using Lagrange multipliers, we have the Lagrangian

with partial derivatives

Set each partial derivative equal to 0:

Subtracting the second equation from the first, we find

Similarly, we can determine that

and

by taking any two of the first three equations. So if

determines a critical point, then

So the smallest value for the sum of squares is

when

.
Answer:
6 terms
Step-by-step explanation:
2 − 2/4 + 2/9 − 2/16 + ...
∑ (-1)ⁿ⁺¹ 2 / n²
Applying alternating series test:
lim(n→∞) 2/n² = 0
2/(n+1)² < 2/n², so the series is decreasing.
Therefore, the series converges.
2/(n+1)² < 0.05
(n+1)²/2 > 20
(n+1)² > 40
n+1 > 6.32
n > 5.32
n = 6
Answer:
Wsp
Step-by-step explanation:
Answer:
9
Step-by-step explanation:
just too the quiz on edge