ANSWER
The correct answer is B
EXPLANATION
The given exponential expression is
We can rewrite this as,
We need to simplify to obtain a positive index, so we apply the following property,
This implies that,
This will finally simplify to,
Therefore the correct answer is B
Wouldn’t be a,or d. I would honestly say B..
Volume of a cylinder = π · radius(r)² · height(h)
Since you didn't provide the radius or the height, I am unable to provide a solution to this problem but hopefully you can solve it on your own now that you have the formula.
<span>we have that
the cube roots of 27(cos 330° + i sin 330°) will be
</span>∛[27(cos 330° + i sin 330°)]
we know that
e<span>^(ix)=cos x + isinx
therefore
</span>∛[27(cos 330° + i sin 330°)]------> ∛[27(e^(i330°))]-----> 3∛[(e^(i110°)³)]
3∛[(e^(i110°)³)]--------> 3e^(i110°)-------------> 3[cos 110° + i sin 110°]
z1=3[cos 110° + i sin 110°]
cube root in complex number, divide angle by 3
360nº/3 = 120nº --> add 120º for z2 angle, again for z3
<span>therefore
</span>
z2=3[cos ((110°+120°) + i sin (110°+120°)]------ > 3[cos 230° + i sin 230°]
z3=3[cos (230°+120°) + i sin (230°+120°)]--------> 3[cos 350° + i sin 350°]
<span>
the answer is
</span>z1=3[cos 110° + i sin 110°]<span>
</span>z2=3[cos 230° + i sin 230°]
z3=3[cos 350° + i sin 350°]<span>
</span>
Answer: Yes, she will have enough trim for all four sides of the square, because the perimeter of the square photo (30.98 inches) is less than 32 inches of trim she has.
Step-by-step explanation:
The formula for calculate the area of a square is:
Where "s" is the lenght of any side of the square.
The formula for calculate the perimeter of a square is:
Where "s" is the lenght of any side of the square.
We know that that the area of the photo is 60 square inches, therefore, we can solve for "s" from the formula and find its value:
Substituting the value of "s" into the formula , we get that the perimeter of the photo is:
Therefore, since Alicia has 32 inches of trim and 
, we can conclude that she will have enough trim for all four sides of the square.
