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Varvara68 [4.7K]

3 years ago

10

What is the smaller x and what is the larger x?

1 answer:

kiruha [24]3 years ago

6 0

both are 2

check

2²+3(2)-10=0

4+6-10=0

10-10=0

0=0

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Write as a fraction or mixed number in simplest form. Show all work please

Gemiola [76]

First you gotta change it to a fraction, which would be 6/10 because it's in the tenths place. Now simplify it, which would be 3/5.

4 0

2 years ago

For every integer k from 1 to 10, inclusive the "k"th term of a certain sequence is given by (−1)(k+1)∗(12k). If T is the sum of

Katena32 [7]

Answer:

Option D. is the correct option.

Step-by-step explanation:

In this question expression that represents the kth term of a certain sequence is not written properly.

The expression is $(-1)^{k+1}(\frac{1}{2^{k}})$ .

We have to find the sum of first 10 terms of the infinite sequence represented by the expression given as $(-1)^{k+1}(\frac{1}{2^{k}})$ .

where k is from 1 to 10.

By the given expression sequence will be $\frac{1}{2},\frac{(-1)}{4},\frac{1}{8}.......$

In this sequence first term "a" = $\frac{1}{2}$

and common ratio in each successive term to the previous term is 'r' = $\frac{\frac{(-1)}{4}}{\frac{1}{2} }$

r = $-\frac{1}{2}$

Since the sequence is infinite and the formula to calculate the sum is represented by

$S=\frac{a}{1-r}$ [Here r is less than 1]

$S=\frac{\frac{1}{2} }{1+\frac{1}{2}}$

$S=\frac{\frac{1}{2}}{\frac{3}{2} }$

S = $\frac{1}{3}$

Now we are sure that the sum of infinite terms is $\frac{1}{3}$ .

Therefore, sum of 10 terms will not exceed $\frac{1}{3}$

Now sum of first two terms = $\frac{1}{2}-\frac{1}{4}=\frac{1}{4}$

Now we are sure that sum of first 10 terms lie between $\frac{1}{4}$ and $\frac{1}{3}$

Since $\frac{1}{2}>\frac{1}{3}$

Therefore, Sum of first 10 terms will lie between $\frac{1}{4}$ and $\frac{1}{2}$ .

Option D will be the answer.

3 0

3 years ago

Can anyone help pls!!!!

Wittaler [7]

Answer:

<h3>3√7 </h3>

√3 × √21

√3 × √3 × √7

(√3)^2 × √7

3 √7

8 0

3 years ago

Read 2 more answers

The probability of being a universal donor is 6% (O-negative-blood type). Suppose that 6 people come to a blood drive.' a) What

Tcecarenko [31]

Answer:

$Mean = 0.36$

$SD = 0.5817$

$P(x=3) = 0.003588$

Step-by-step explanation:

Given

Let

A = Event of being a universal donor.

So:

$P(A) = 0.06$

$n = 6$

Solving (a): Mean and Standard deviation.

The mean is:

$Mean = np$

$Mean = 6 * 0.06$

$Mean = 0.36$

The standard deviation is:

$SD = \sqrt{np(1-p)}$

$SD = \sqrt{6*0.06*(1-0.06)}$

$SD = \sqrt{0.3384}$

$SD = 0.5817$

Solving (b): P(x = 3)

The event is a binomial event an dthe probability is calculated as:

$P(x) = ^nC_x * p^x * (1-p)^{n-x}$

So, we have:

$P(x=3) = ^6C_3 * 0.06^3 * (1-0.06)^{6-3}$

$P(x=3) = ^6C_3 * 0.06^3 * (1-0.06)^3$

$P(x=3) = 20 * 0.06^3 * (1-0.06)^3$

$P(x=3) = 0.003588$

7 0

2 years ago

PLEASE HELP ASAP!!! I WILL GIVE 13 POINTS: Translate into algebraic expression- n−1 increased by 110%

garik1379 [7]

Answer:

(n-1)2.1

Step-by-step explanation:

Since it already gives you a vaariable <u>n</u>, -->

P (n-1) -->

COnvert 110% to 2.1 / decimal

--> multiply

(n-1)2.1

Hope this helps!

5 0

3 years ago