We do this by using the formula $\displaystyle nCr=\frac{n!}{r!(n-r)!}$ which describes the number of ways we can choose $r$ objects given $n$ possible choices. So, if $n=7$ and $r=4$ , then:

$_4C_7=\frac{7!}{4!(7-4)!}\\\\_4C_7=\frac{7*6*5*4!}{4!*3!}\\\\_4C_7=\frac{210}{6}\\\\_4C_7=35$

Hence, the teacher can make 35 different geometry quizzes.

3 0

2 years ago

A. y = |x - 4| - 2

professor190 [17]

The is C
Hope this help!

7 0

3 years ago

Please help on number 3.

castortr0y [4]

Plug in 50 for x on the equation for the trend line

6 0

3 years ago

What is 6 1/2 - 2 2/5 - 2 1/2 =

VikaD [51]

Answer:

1 3/5

Step-by-step explanation:

Change to mixed fractions, that'll give:

13/2 - 12/5 - 5/2

Using lcm:

16/10

Change back to mixed fractions:

1 6/10

Lowest term:

1 3/5

4 0

3 years ago