3 years ago

Please please help me with this!!!!!!!

Mathematics

1 answer:

Alborosie3 years ago

5 0

Answer:

Step-by-step explanation:

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3 years ago

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A recursive rule for a geometric sequence is a1=2; an= 4/9 an-1

Oxana [17]

A recursive rule for a geometric sequence:

$a_1\\\\a_n=r\cdot a_{n-1}$

---------------------------------------------------

$a_1=2;\ a_n=\dfrac{4}{9}a_{n-1}\to r=\dfrac{4}{9}$

---------------------------------------------------

The exciplit rule:

$a_n=a_1r^{n-1}$

Substitute:

$a_n=2\left(\dfrac{4}{9}\right)^{n-1}=2\cdot\left(\dfrac{4}{9}\right)^n\cdot\left(\dfrac{4}{9}\right)^{-1}=2\cdot\left(\dfrac{4}{9}\right)^n\cdot\dfrac{9}{4}\\\\\boxed{a_n=\dfrac{9}{2}\cdot\left(\dfrac{4}{9}\right)^n}$

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Numbers 2-4 Will choose brainliest

Sever21 [200]

Answer:

2. 9, 8+9

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Step-by-step explanation:

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3 years ago

Given the function f(x)=2x-1<br> Evaluate: <br>a) 2f(x) <br> b) f(2x)

Dmitrij [34]

Answer:

a) 2f(x) = 4x - 2

b) f(2x) = 4x - 1

Explanation:

Given function:

f(x) = 2x - 1

a) 2f(x)

2f(x) = 2(2x - 1)

= 4x - 2

b) f(2x)

f(2x) = 2(2x) - 1

= 4x - 1

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2 years ago