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Soloha48 [4]
3 years ago
6

Can someone please help

Mathematics
1 answer:
Westkost [7]3 years ago
4 0

Answer: B & D

<u>Step-by-step explanation:</u>

A is not correct because it says "in the city" instead of "in Elan's school"

C is not correct because it says do NOT ....

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4) A right triangle has a hypotenuse length of 10 and one of its legs has a
Rudiy27

Answer: 8

Step-by-step explanation:

8 0
3 years ago
Use the figure and flowchart proof to answer the question:
KatRina [158]

Answer:

tSubstitution Property of Equality

Step-by-step explanation:

I took the test and that was the answer

4 0
3 years ago
One circular table has a diameter of 8 ft, and another circular table has a diameter of 12 ft. How much greater is the area of t
mezya [45]

Answer:

20π sq ft ≈ 62.83 sq ft

Step-by-step explanation:

Area of table with diameter 8 ft = π*8^2/4 = 16π

Area of table with diameter 12 ft = π*12^2/4 = 36π

Difference between the area of the tables ;

= 36π - 16π

= 20π sq ft ≈ 62.83 sq ft                              ( π = 3.14)

8 0
3 years ago
Read 2 more answers
What is the sum or difference of 5/7 - 1/3
Hatshy [7]
ANSWER: 8/21

Step:
1. Find the GCF (Greatest Common Factor)
           The two denominator which is the bottom number have to be the same ALWAYS when adding and subtracting the fraction. So to find the GCF, you keep multiplying until you see the same number, only use the bottom number to find the GCF
      7: 7, 14, 21, 28
      3: 3, 6, 9, 12, 15, 18, 21, 24, 27
         GCF= 21

2.  5/7 -1/3
    Multiple both to get 21
        5/7 x 3/3 = 15/21
        1/3 x 7/7 = 7/21

3. Sove
     15/21 - 7/21
        = 8/21

7 0
2 years ago
Please please please need help on 3 and 4 I’m really lost on them
Alex73 [517]

Answer:

1) Option c) is correct ie., 5 real and o non-real

2) Option b) is correct ie., (4, \frac{1}{2}, \frac{1}{2}, 2,2)

Step-by-step explanation:

Given polynomial function is f(x)=x^5-3x^3-2

To find zeros equate f(x) to zero ie.,  f(x)=0

x^5-3x^3-2=0

By synthetic division

     |   1     0    -3      0      -2

-1  |   0    -1      1      2      2

     |_________________

        1      -1      -2     2      0

Therefore x=-1 is a zero

x^3-x^2-2x+2=0

      |  1    -1     -2    2

1      |  0     1     0     2

      |___________________

          1     0   -2   0

x=1 is the zero

x^2 -2 =0

x=\pm\sqrt{2}

x=\sqrt{2} and

x=\sqrt{-2}

Option c) is correct ie., 5 real and o non-real

2) Given polynomial function is f(x)=(x-4)(2x-1)^2(x-2)^2

To find zeros equate f(x) to zero ie.,  f(x)=0

                                                            (x-4)(2x-1)^2(x-2)^2=0

(x-4)=0 (or) (2x-1)^2=0 or (x-2)^2=0

Therefore x=4, x=\frac{1}{2} of multiplicity of 2 and x=2 multiplicity of 2

Option b) is correct ie., (4, \frac{1}{2}, \frac{1}{2}, 2,2)

5 0
3 years ago
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