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3 years ago

What are potential roots of p(x) = x4 − 9x2 − 4x + 12

Mathematics

2 answers:

AnnyKZ [126]3 years ago

7 0

Answer: +/- 2,+/- 4,+/- 3,+/- 6,+/- 12

Step-by-step explanation:

they all are potential roots.

weeeeeb [17]3 years ago

6 0

Hello :
<span> x4 − 9x2 − 4x + 12 = x²(x²-9)-4(x-3)
=x²(x-3)(x+3)-4(x-3)
= (x-3)(x²(x+3)-4)
= (x-3)(x3+3x²-4)
= (x-3)(x-1)(x²+4x+4)
</span>x4 − 9x2 − 4x + 12 = (x-3)(x-1) (x+2)²
<span> potential roots is : 3 ; 1 :-2</span>

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Forgot to do this over winter break. Its due tomorrow and I haven't used my brain for 2 weeks. HELPPP (may have to zoom in)

ANEK [815]

1. 60,30,90 right triangle. y will be hypotenuse/2, x will be
hypotenuse*sqrt(3)/2. So x = 16*sqrt(3)/2 = 8*sqrt(3), approximately 13.85640646
y = 16/2 = 8
2. 45,45,90 right triangle (2 legs are equal length and you have a right angle).
X and Y will be the same length and that will be hypotenuse * sqrt(2)/2. So
x = y = 8*sqrt(2) * sqrt(2)/2 = 8*2/2 = 8
3. Just a right triangle with both legs of known length. Use the Pythagorean theorem
x = sqrt(12^2 + 5^2) = sqrt(144 + 25) = sqrt(169) = 13
4. Another right triangle with 1 leg and the hypotenuse known. Pythagorean theorem again.
y = sqrt(1000^2 - 600^2) = sqrt(1000000 - 360000) = sqrt(640000) = 800  5. A 45,45,90 right triangle. One leg known. The other leg will have the same length as the known leg and the hypotenuse can be discovered with the Pythagorean theorem.  x = 6. y = sqrt(6^2 + 6^2) = sqrt(36+36) = sqrt(72) = sqrt(2 * 36) = 6*sqrt(2), approximately 8.485281374
6. Another 45,45,90 triangle with the hypotenuse known. Both unknown legs will have the same length. And Pythagorean theorem will be helpful.
x = y.
12^2 = x^2 + y^2
12^2 = x^2 + x^2
12^2 = 2x^2
144 = 2x^2
72 = x^2
sqrt(72) = x
6*sqrt(2) = x
x is approximately 8.485281374
7. A 30,60,90 right triangle with the short leg known. The hypotenuse will be twice the length of the short leg and the remaining leg can be determined using the Pythagorean theorem.
y = 11*2 = 22.
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8. A 30,60,90 right triangle with long leg known. Can either have fact that in that triangle, the legs have the ratio of 1:sqrt(3):2, or you can use the Pythagorean theorem. In this case, I'll use the 1:2 ratio between the unknown leg and the hypotenuse along with the Pythagorean theorem.
x = 2y
y^2 = x^2 - (22.5*sqrt(3))^2
y^2 = (2y)^2 - (22.5*sqrt(3))^2
y^2 = 4y^2 - 1518.75
-3y^2 = - 1518.75
y^2 = 506.25 = 2025/4
y = sqrt(2025/4) = sqrt(2025)/sqrt(4) = 45/2
Therefore:
y = 22.5
x = 2*y = 2*22.5 = 45
9. Just a generic right triangle with 2 known legs. Use the Pythagorean theorem.
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10. Another right triangle, another use of the Pythagorean theorem.
x = sqrt(50^2 - 14^2) = sqrt(2500 - 196) = sqrt(2304) = 48

8 0

3 years ago

An object travels 4/5 miles in one-half hour. What is its speed?

Ilia_Sergeevich [38]

Answer:

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7 0

3 years ago

Please help. Don’t understand this math problem!

oksian1 [2.3K]

Answer:

{ 4 }

Step-by-step explanation:

First you need to solve the equation. Then you need to write the solutions as a set.

I like to use a graphing calculator to solve equations involving roots. That helps avoid extraneous solutions. Here, the graph of the left side intersects the graph of the right side at x=4. There is exactly one solution, so the solution set is ...

{ 4 }

Solving this algebraically, you would isolate the radical, then "undo" it by squaring both sides of the equation. Then solve the resulting quadratic. That will have 2 solutions, only one of which will work in the original equation.

√(5x +16) -2 = 3x -8 . . . . given

√(5x +16) = 3x -6 . . . . . . add 2

5x +16 = (3x -6)^2 . . . . . square both sides

5x +16 = 9x^2 -36x +36 . . . . expand the square

9x^2 -41x +20 = 0 . . . . . . subtract (5x+16) to put into standard form

Factors of 9·20 = 180 that have a sum of 41 are 5 and 36, so we can rewrite this equation as ...

9x^2 -36x -5x +20 = 0

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(9x -5)(x -4) = 0

The values of x that make this equation true are the values that make the factors be zero: 5/9 and 4. Trying these in the equation, we find ...

√(5(5/9) +16) -2 = 13/3 -2 = 2 1/3 . . . . value of the left side for x = 5/9

3(5/9) -8 = -6 1/3 . . . . . . value of the right side for x=5/9; not the same

x = 5/9 is NOT A SOLUTION

√(5(4)+16) -2 = √36 -2 = 4 . . . . value of the left side for x = 4

3(4) -8 = 12 -8 = 4 . . . . . . value of the right side for x=4. These are the same, so ...

x = 4 is a solution

The set of solutions is then ...

{ 4 } . . . . . solution set

5 0

3 years ago

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Darya [45]

Answer:

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Step-by-step explanation:

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