A certain oil refinery keeps intermediate products in 8 tanks. There are 15 pumps of varying capacity that can be assigned to pu mp the intermediate products from the 8 tanks into a final-product tank. Question: How many ways can you assign the 15 pumps to the 8 tanks so that each tank gets at least one pump?
1 answer:
Answer:
Step-by-step explanation:
This question is permutation problem. permutations is the number of arrangements or orderings within a constant group.
The formula for permutation is given as
nPk = n!÷(n-k)!
Where n is the number of objects, k is the is the number of objects we want to chose from.
Solution to the question
15P8 = 15!÷(15-8)!
= 15!÷7!
= 15×14×13×12×11×10×9×8×7×6×5×4×3×2×1÷7×6×5×4×3×2×1
= 259459200
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