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LuckyWell [14K]
4 years ago
5

A certain oil refinery keeps intermediate products in 8 tanks. There are 15 pumps of varying capacity that can be assigned to pu

mp the intermediate products from the 8 tanks into a final-product tank. Question: How many ways can you assign the 15 pumps to the 8 tanks so that each tank gets at least one pump?
Mathematics
1 answer:
Furkat [3]4 years ago
4 0

Answer:

Step-by-step explanation:

This question is permutation problem. permutations is the number of arrangements or orderings within a constant group.

The formula for permutation is given as

nPk = n!÷(n-k)!

Where n is the number of objects, k is the is the number of objects we want to chose from.

Solution to the question

15P8 = 15!÷(15-8)!

= 15!÷7!

= 15×14×13×12×11×10×9×8×7×6×5×4×3×2×1÷7×6×5×4×3×2×1

= 259459200

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Given :

Emily sells erasers for $2 per package and pencils for $5 per package. she sells 220 total packages and earns $695.

To Find :

The number of packages of erasers and pencils that were sold .

Solution :

Let, number of erasers are x and pencils are y.

So, x + y = 220    ....1

Also, 2x + 5y = 695   ....2

Solving equation 1 and 2, we get :

2(220-y)+5y = 695\\\\440 - 2y + 5y = 695\\\\3y = 255\\\\y=85

x = 220 - 85 = 135

Therefore, the number of packages of erasers and pencils that were sold are 135 and 85 respectively.

Hence, this is the required solution.

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