3 years ago

Can somebody help me with all the questions?

1 answer:

6 0

The data isn't proportional because there is a y-intercept.
20/1 is not equal to 28/2, which isnt equal to 36/3 and so on

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Is 2/11 bigger than 3/12

Tju [1.3M]

2/11 ≈ 0.18 3/12 = 0.25.

So the answer is no, 2/11 isn't bigger than 3/12.

I hope this helps!

6 0

3 years ago

Read 2 more answers

The linear scale factor of two similar solids is given. Then the surface area and volume of the smaller figure are also given. F

katen-ka-za [31]

Answer:

SA:48 V:144

Step-by-step explanation:

4 0

3 years ago

This is for Pre-Calc, so please use Pre-Calc terms. You do not have to answer number 1. I have it done already. I need help ASAP

Dominik [7]

Answer:

Step-by-step explanation:

a1=2a7 because the square route of (Tan) is 49 so it 2a7tan49 fa10 the answer is b

6 0

3 years ago

Factor: 81y^2-49 Your answer

oksian1 [2.3K]

Answer:(9y-7)(9y+7)

Step-by-step explanation:

81y^2-49

=(9y)^2-(7)^2

=(9y-7)(9y+7)

4 0

2 years ago

Find an upper limit for the zeroes 2x^4 -7x^3 + 4x^2 + 7x - 6 = 0

erik [133]

Answer-

2 is the upper limit for the zeros.

Solution-

The given function f(x) is,

$2x^4 -7x^3 + 4x^2 + 7x - 6 = 0$

For calculating the zeros,

$\Rightarrow f(x)=0$

$\Rightarrow 2x^4 -7x^3 + 4x^2 + 7x - 6 = 0$

$\Rightarrow 2x^4-4x^3-3x^3+6x^2-2x^2+ 4x+3x-6=0$

$\Rightarrow 2x^3(x-2)-3x^2(x-2)-2x(x-2)+3(x-2)=0$

$\Rightarrow (x-2)(2x^3-3x^2-2x+3)=0$

$\Rightarrow (x-2)(x^2(2x-3)-1(2x-3))=0$

$\Rightarrow (x-2)(x^2-1)(2x-3)=0$

$\Rightarrow (x-2)(x+1)(x-1)(2x-3)=0$

$\Rightarrow x-2=0,\ x+1=0,\ x-1=0,\ 2x-3=0$

$\Rightarrow x=2,\ x=-1,\ x=1,\ x=\frac{3}{2}$

From all the 4 roots, it can be obtained that 2 is the greatest zero.

7 0

3 years ago