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ehidna [41]
3 years ago
10

Solve the following equation and determine if it has one solution, no solution, or infinitely many solutions: 3x+1−3(x−1)=4

Mathematics
2 answers:
vaieri [72.5K]3 years ago
7 0

Answer:

1/3  , only one solution

Step-by-step explanation:

3x-1 = 1-3x

3x-1 = -3x+1

6x-1 = 1

6x = 2

x = 1/3

mel-nik [20]3 years ago
6 0

Answer:

Infinitely many solutions.

Step-by-step explanation:

3x+1-3(x-1)=4\\\\3x+1-1-3(x-1)=4-1\\\\3x-3(x-1)=3\\\\3x-3x-3=3\\\\\boxed{3=3}

Hope this helps.

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Read 2 more answers
Which is a factor of 6x2 + x − 7?<br><br> x + 1<br> 2x + 1<br> 6x + 7<br> 3x + 7
katrin [286]

6x2 + x - 7

= (6x + 7)(x - 1)

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How are terminating decimals different from repeating decimals
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4 years ago
How do you factor this trinomial? :
Nezavi [6.7K]
The pic is blurry, but looks like 18x²-21x-15
(3x-5)(6x+3) is the factored form. 
3 and 6 are the factors of 18
-5, 3 or -3, 5 are the factors of -15
I line them up like this
3   -5
6    3
then I multiple them diagonally: 3*3=9, -5*6=-30, the sum of 9 and -30 is exactly -21, the coefficient for x. (If the sum doesn't make -21, I'd switch -5 and 3, or change to -3 and 5 to try again.) 
so the factored form is (3x-5)(6x+3)


5 0
4 years ago
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