Answer: D
Step-by-step explanation:
You need a calculator for this cause the numbers are really large. I used a fx-9860GII Casio calculator. I put the equations on the graph mode. And then I got the x➡️0 for both equations.
I got x=0, y=5000 for the first equation
x=0, y=5200 for the new one.
You can see the y is (5200-5000)=200 more than the old equation. As the x is 0 for both that means the new one moved 200 up for the new one. It goes up cause its positive number .
I put the pictures so you can understand what I'm saying.
Plug x = 0 into the function
f(x) = x^3 + 2x - 1
f(0) = 0^3 + 2(0) - 1
f(0) = -1
Note how the result is negative. The actual number itself doesn't matter. All we care about is the sign of the result.
Repeat for x = 1
f(x) = x^3 + 2x - 1
f(1) = 1^3 + 2(1) - 1
f(1) = 2
This result is positive.
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We found that f(0) = -1 and f(1) = 2. The first output -1 is negative while the second output 2 is positive. Going from negative to positive means that, at some point, we will hit y = 0. We might have multiple instances of this happening, or just one. We don't know for sure. The only thing we do know is that there is at least one root in this interval.
To actually find this root, you'll need to use a graphing calculator because the root is some complicated decimal value. Using a graphing calculator, you should find the root to be approximately 0.4533976515
Answer:
-6, 6
Step-by-step explanation:
I hope this helps :)
Kelly? Im not sure actually... Im going with Kelly but im probably wrong
