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Verizon [17]
3 years ago
8

When x = 3 and y = 5, by how much does the value of 3x2 – 2y exceed the value of 2x2 – 3y ?

Mathematics
2 answers:
Feliz [49]3 years ago
8 0
The answer goes up by 14 because the first problem equals 8 and the second problem equals --3 therefor the difference is 14
fgiga [73]3 years ago
4 0
3\cdot3^2-2\cdot5=27-10=17\\
2\cdot3^2-3\cdot5=18-15=3\\\\
17-3=14

By 14.
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You have $5.00 in quarters and dimes. You have a total of 41 coins. How many of the coins are quarters?
Dmitry_Shevchenko [17]
One because if you put two then the would be 50 and thats over 41
8 0
3 years ago
Help meeee with this questionnnnnnnnnn!!!!!!!!!!!!
Dafna1 [17]

Given:

The scale factor between two circles is \dfrac{2x}{5y}.

To find:

The ratio of their areas.

Solution:

We know that, all circles are similar.

The ratio of the areas of similar figures is equal to the ratio of squares of their corresponding sides or equal to the square of ratio of their corresponding sides.

The scale factor is the ratio of the corresponding sides.

Ratio of areas of circles = Square of scale factor between two circles

\text{Ratio of areas of circles}=\left(\dfrac{2x}{5y}\right)^2

\text{Ratio of areas of circles}=\dfrac{(2x)^2}{(5y)^2}

\text{Ratio of areas of circles}=\dfrac{4x^2}{25y^2}

Therefore, the correct option is D.

3 0
3 years ago
A value is in the domain if there is a ____ on the graph of the function at that x-value
fredd [130]
<span>A value is in the domain if there is a point on the graph of the function at that x-value</span>
5 0
3 years ago
Solve the following triangle in which given sides are<br> a=7 b=7 c=9
blagie [28]
We have an isosceles triangle;
A=opposite angle side a.
B=opposite angle side b.
C=opposite angle side c.

A=B
Method 1:

We can divide the isosceles triangle in two right triangles,
hypotenuse=7
side=9/2=4.5

B=A=arccossine (4.5/7)=49.994799...º≈50º
C/2=90º-50º=40º  ⇒ C=2*40º=80º

Answer:
a=7;  A=50º
b=7;  B=50º
<span>c=9;  C=80º

Method 2:
Law of cosines:
a²=b²+c²-2bcCosA  ⇒CosA=(a²-b²-c²)/(-2bc)
CosA=(49-49-81) / (-126)=0.642857
A=arco cos (81/126)≈50º

B=A=50º

A+B+C=180º
50º+50º+C=180º
C=180º-100º
C=80º

Answer:

</span>a=7;  A=50º
b=7;  B=50º
<span>c=9;  C=80º</span>

8 0
3 years ago
PLS SOLVE AND EXPLAIN
Sonja [21]
The answer to the question

6 0
3 years ago
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