All categories

3 years ago

When x = 3 and y = 5, by how much does the value of 3x2 – 2y exceed the value of 2x2 – 3y ?

2 answers:

8 0

The answer goes up by 14 because the first problem equals 8 and the second problem equals --3 therefor the difference is 14

fgiga [73]3 years ago

4 0

$3\cdot3^2-2\cdot5=27-10=17\\
2\cdot3^2-3\cdot5=18-15=3\\\\
17-3=14$

By 14.

You might be interested in

In a right triangle sin A=

kherson [118]

Answer:

$sinA=\frac{opposite}{hypotenuse}$

Step-by-step explanation:

Soh-cah-toa is a great way to remember:

$sin=\frac{opposite}{hypotenuse}\\ cin=\frac{adjacent}{hypotenuse}\\ tan=\frac{opposite}{adjacent}$

You just remember the first letters : sine= opposite/hypotenuse , for example.

6 0

3 years ago

Read 2 more answers

The system of equations 2y = 14 - 2x and y=-x+ 7 is

Ratling [72]

Answer:

Infinitely many solutions

Step-by-step explanation:

2y=14-2x

y=-x+7

------------

2(-x+7)=14-2x

-2x+14=14-2x

-2x-(-2x)=14-14

-2x+2x=0

0=0

infinitely many solutions

6 0

3 years ago

Read 2 more answers

4^0 + 5^0 + 6^0 = (4+5+6)^0<br> a)True<br> b)False

Yuri [45]

Step-by-step explanation:

false

4^0 + 5^0 + 6^0= 1+1+1=3

(4+5+6)^0= 3⁰=1

1≠3

7 0

3 years ago

Read 2 more answers

F(x)= x to the 4th power + x to the 3 power - 11 x to the 2 power - 9x + 18

postnew [5]

Graficamente ficará :

3 0

3 years ago

The matrix C=[1,-2_-3,7] was used to encode a phrase to [7,-28,-25,-35,-2_-21,107,90,123,17]. Find C^-1 and use it to decode the

posledela

$C= \left[\begin{array}{cc}1&-2\\-3&7\end{array}\right] \\ C^{-1}= \left[\begin{array}{cc}7&2\\3&1\end{array}\right] \\ \left[\begin{array}{cc}7&2\\3&1\end{array}\right] \times \left[\begin{array}{ccccc}7&-28&-25&-35&-2\\-21&107&90&123&17\end{array}\right] \\ =\left[\begin{array}{ccccc}49-42&-196+214&-175+180&-245+246&-14+34\\21-21&-84+107&-75+90&-105+123&-6+17\end{array}\right] \\ =\left[\begin{array}{ccccc}7&18&5&1&20\\0&23&15&18&11\end{array}\right]$
is the required matrix.

6 0

3 years ago