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3 years ago

When x = 3 and y = 5, by how much does the value of 3x2 – 2y exceed the value of 2x2 – 3y ?

2 answers:

8 0

The answer goes up by 14 because the first problem equals 8 and the second problem equals --3 therefor the difference is 14

fgiga [73]3 years ago

4 0

$3\cdot3^2-2\cdot5=27-10=17\\
2\cdot3^2-3\cdot5=18-15=3\\\\
17-3=14$

By 14.

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A box of Georgia peaches has 3 bad and 12 good peaches. (a) If you make a peach cobbler of 12 peaches randomly selected from the

Eddi Din [679]

Answer:

a) 0.21% probability that there are no bad peaches in the peach cobbler.

b) 99.79% probability of having at least 1 bad peach in the peach cobbler

c) 7.91% probability of having exactly 2 bad peaches in the peach cobbler.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the peaches are chosen is not important. So the combinations formula is used to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

(a) If you make a peach cobbler of 12 peaches randomly selected from the box, what is the probability that there are no bad peaches in the peach cobbler?

Desired outcomes:

12 good peaches, from a set of 12. So

$D = C_{12,12} = \frac{12!}{12!(12 - 12)!} = 1$

Total outcomes:

12 peaches, from a set of 15. So

$T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455$

Probability:

$p = \frac{D}{T} = \frac{1}{455} = 0.0021$

0.21% probability that there are no bad peaches in the peach cobbler.

(b) What is the probability of having at least 1 bad peach in the peach cobbler?

Either there are no bad peaches, or these is at least 1. The sum of the probabilities of these events is 100%. So

p + 0.21 = 100

p = 99.79

99.79% probability of having at least 1 bad peach in the peach cobbler

(c) What is the probability of having exactly 2 bad peaches in the peach cob- bler?

Desired outcomes:

2 bad peaches, from a set of 3.

One good peach, from a set of 12.

$D = C_{3,2}*C_{12,1} = \frac{3!}{2!(3-2)!}*\frac{12!}{1!(12 - 1)!} = 36$

Total outcomes:

12 peaches, from a set of 15. So

$T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455$

Probability:

$p = \frac{D}{T} = \frac{36}{455} = 0.0791$

7.91% probability of having exactly 2 bad peaches in the peach cobbler.

3 0

3 years ago

95/8 -17/8 what does it equal

Rufina [12.5K]

Input the fraction = 95/8
Integer =11
Fraction part = 7/8
Answer = 11.875

8 0

3 years ago

Read 2 more answers

HELP ME PLEASE I SUCK AT MATH I need work shown on this and I only need 3of Them Done Or Two So I Can Do the last one or soo I T

sineoko [7]

Simple 200 is the answer

5 0

3 years ago

What is the square root of y^3

tia_tia [17]

Answer:

$y^{\frac{3}{2}$

Step-by-step explanation:

Let $m=\sqrt{y^3}$

$m=(y^3)^{\frac{1}{2}}\\\\m=y^{3\times \frac{1}{2}}\ \ \ \ \ \ \ \ \ [as\ (x^a)^b=x^{ab}]\\\\m=y^{\frac{3}{2}$

7 0

3 years ago

Tom received a $70 gift card for a cafe. He used it to buy some coffee that cost $7.73 per pound. After buying the coffee, he ha

mart [117]

Answer: He bought 6 pounds of coffee.

Step-by-step explanation:

Money he have = 70

money he used to buy = 70.00 - 23.62 = 46.38

7.73 dollar = 1 pound

1 dollar = 1/(7.73) = 100/773 pound

46.38 dollar = (100/773) * 46.38 = 6 pound

5 0

3 years ago