Answer: Yes these triangles are similar
Step-by-step explanation:
First lets write down what we know just to make life easier
x=9
TL should be similar to CH
LY should be similar to KH
The angles should be equal due to SAS
So the first thing we know is true is the fact that they have equal angles. Now we have to find out if the sides are similar or if they change by the same ratio to the other. If TL is similar to CH and TL=25 and CH=10 what is the change in size or dilation. Division should do the trick so 25/10=2.5 so TY is greater than CH by a factor of 10. Which means that LY should also be greater than KH by a factor of 2.5. If we are told that x=9 than side LY or 4(9)-1=35 and KH 9+5=14
So side KH is 14 and LY is 35. Now to check if they are similar then KH should be greater by a factor of 2.5. If this is not true than the sides are not similar. 35/2.5=14
Since 35 divided by 2.5 is 14 we can tell both sides TL and LY are greater than KH and CH by a factor of 2.5
Hope this helps.
Answer:98.9276
Step-by-step explanation:
The table displays the amount of time, in minutes, Jordan rode his bike for five days. How many total hours did Jordan ride his bike in the five days? DayTime (minutes)11 4545 22 109109 33 5151 44 121121 55 3838 Jordan rode his bike total hours in the five days.
Answer:
The Arch is 630 ft tall
Step-by-step explanation:
Answer:
Step-by-step explanation: This is the quadratic function:
h(x)=ax²+bx+c
We have two points:
(1,58)
(2,112)
Now, we calculate this quadratic funtion.
we assume that h(0)=0
Therefore:
a(0)²+b(0)+c=0
c=0
(1,58)
a(1)²+b(1)=58
a+b=58 (1)
(2,112)
a(2)²+b(2)=112
4a+2b=112
2a+b=56 (1)
With the equations (1) and (2) we make a system of equations:
a+b=58
2a+b=56
we can solve this system of equations by reduction method.
-(a+b=58)
2a+b=56
---------------------
a=-2
-2(a+b=58)
2a+b=56
-------------------
-b=-60 ⇒ b=60
The function is:
h(x)=ax²+bx+c
h(x)=-2x²+60x
Now find the height, in feet, of the rock after 10 seconds in the air.
h(10)=-2(10)²+60(10)
h(10)=-200+600=400
Answer: 400 ft.