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Virty [35]
3 years ago
14

Greg has collected 4,385 pennies and Hannah has collected 3,899 pennies. How many times as great as the value of 3 in 4,385 is t

he value of the 3 in 3,899?
Mathematics
2 answers:
wel3 years ago
4 0
Answer: The 3 in 3,899 is 10 times the 3 in 4,385!
Korvikt [17]3 years ago
4 0

Answer:

\frac{1}{10}\text{ times}

Step-by-step explanation:

Given,

The numbers are,

4,385, 3,899

∵ 4385 = 4000 + 300 + 80 + 5

And, 3899 = 3000 + 800 + 90 + 9

So, the value of 3 in 4385 = 300

The value of 3 in 3899 = 3000

\because \frac{\text{The value of 3 in 4385}}{\text{The value of 3 in 3899}}=\frac{300}{3000}

=\frac{1}{10}

Hence, the value of 3 in 4,385 is \frac{1}{10} times greater than the value of the 3 in 3,899.

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What is the solution for the equation StartFraction 5 Over 3 b cubed minus 2 b squared minus 5 EndFraction = StartFraction 2 Ove
wolverine [178]

Answer:

The solutions are:

b=0,\:b=4

Step-by-step explanation:

Considering the expression

  • \frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}

Solving the expression

\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}

\mathrm{Apply\:fraction\:cross\:multiply:\:if\:}\frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c

5\left(b^3-2\right)=\left(3b^3-2b^2-5\right)\cdot \:2

5b^3-10=6b^3-4b^2-10

\mathrm{Switch\:sides}

6b^3-4b^2-10=5b^3-10

6b^3-4b^2-10+10=5b^3-10+10

6b^3-4b^2=5b^3

\mathrm{Subtract\:}5b^3\mathrm{\:from\:both\:sides}

6b^3-4b^2-5b^3=5b^3-5b^3

b^3-4b^2=0

Using\:the\:Zero\:Factor\:Principle: if\:\mathrm ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

So,

b=0,b-4=0

b=0,b=4

Therefore, the solutions are:

b=0,\:b=4

4 0
3 years ago
Read 2 more answers
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ad-work [718]

Answer:

{x| -2 ≤ x < 5}

Step-by-step explanation:

The domain is the x value in a graph, function e.t.c. From the farthest point to the left of the x-axis, we see -2. And from the farthest point to the right of the x-axis, we see 5. Therefore, the domain is {x| -2 ≤ x < 5}, Option C

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8 0
2 years ago
Make <br> x<br> the subject of the formula<br> x<br> −<br> 3<br> =<br> q
lakkis [162]

Answer:

x = q + 3

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
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Equality Properties

Step-by-step explanation:

<u>Step 1: Define Equation</u>

x - 3 = q

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Add 3 to both sides:          x = q + 3
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2 years ago
Y=-3/2x+2 Help please!
skad [1K]
 I believe this is the correct answer Y= 3/2x+2
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Which statement best explains how to find the area of the kite?
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I think it is a D I'm not really sure

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