Answer:
m^2 +my-my-y^2
Step-by-step explanation:
just dont simplify
Answer and Step-by-step explanation:
Given that probability of you winning each game = 0.68
And probability of you winning next game = 0.81
Your friend's chance of winning/you losing would be = 1-0.68= 0.32
also his chance of winning next game = 0.73
To find probability that you would win the series given that you need to win two games to win the series
= probability that you win first game and second game+ probability that you win first game, lose second game and win third game + probability that you lose first game, win second game and win third game
= 0.68*0.81+0.68*0.32*0.68+0.32*0.68*0.81
=0.8750
Therefore probability that you would win the series = 0.8750
Note: here we found the probability of winning by adding(or) up the three possible combinations that would result in a win
P>-2 or p < 5 is your answer
Answer:
A number minus the product of
4
and its reciprocal is less than zero. Find the numbers which satisfy this condition.
AAny number less than
−
2
or between
0
and
2
BAny number between
−
2
and
2
CAny number less than
2
DAny number between
0
and
2
Solution
Let the number be x
Then
x
−
(
4
×
1
x
)
≤
0
⇒
x
≤
4
x
⇒
x
2
≤
4
⇒
|
x
|
≤
2
⇒
−
2
≤
x
≤
2
Step-by-step explanation: