Answer:
60n seconds
Step-by-step explanation:
In 1 min, there are 60 seconds
So,
1 min = 60 secs
For n minutes, it becomes:
=> 60n seconds
Answer:
a. 38.19m/s
b. 38.605m/s
c. 38.937m/s
d. 39.0117m/s
e. 39.01917m/s
Step-by-step explanation:
The average velocity is defined as the relationship between the displacement that a body made and the total time it took to perform it. Mathematically is given by the next formula:
![v_a_v_g = \frac{\Delta x}{\Delta t} =\frac{x_f-x_i}{t_f-t_i}](https://tex.z-dn.net/?f=v_a_v_g%20%3D%20%5Cfrac%7B%5CDelta%20x%7D%7B%5CDelta%20t%7D%20%3D%5Cfrac%7Bx_f-x_i%7D%7Bt_f-t_i%7D)
Where:
![x_f=Final\hspace{3}distance\hspace{3}traveled\\x_i=Initial\hspace{3}distance\hspace{3}traveled\\t_f=Final\hspace{3}time\hspace{3}interval\\t_i=Initial\hspace{3}time\hspace{3}interval](https://tex.z-dn.net/?f=x_f%3DFinal%5Chspace%7B3%7Ddistance%5Chspace%7B3%7Dtraveled%5C%5Cx_i%3DInitial%5Chspace%7B3%7Ddistance%5Chspace%7B3%7Dtraveled%5C%5Ct_f%3DFinal%5Chspace%7B3%7Dtime%5Chspace%7B3%7Dinterval%5C%5Ct_i%3DInitial%5Chspace%7B3%7Dtime%5Chspace%7B3%7Dinterval)
a. Let's find h(3) and h(4) using the data provided by the problem:
![h(3)=44(3)-0.83(3^2)=124.53=x_i\\h(4)=44(4)-0.83(4^2)=162.72=x_f](https://tex.z-dn.net/?f=h%283%29%3D44%283%29-0.83%283%5E2%29%3D124.53%3Dx_i%5C%5Ch%284%29%3D44%284%29-0.83%284%5E2%29%3D162.72%3Dx_f)
The average velocity over the interval [3, 4] is :
![v_a_v_g=\frac{162.72-124.53}{4-3} =38.19m/s](https://tex.z-dn.net/?f=v_a_v_g%3D%5Cfrac%7B162.72-124.53%7D%7B4-3%7D%20%3D38.19m%2Fs)
b. Let's find h(3.5) using the data provided by the problem:
![h(3.5)=44(3.5)-0.83(3.5^2)=143.8325=x_f](https://tex.z-dn.net/?f=h%283.5%29%3D44%283.5%29-0.83%283.5%5E2%29%3D143.8325%3Dx_f)
The average velocity over the interval [3, 3.5] is :
![v_a_v_g=\frac{143.8325-124.53}{3.5-3} =38.605m/s](https://tex.z-dn.net/?f=v_a_v_g%3D%5Cfrac%7B143.8325-124.53%7D%7B3.5-3%7D%20%3D38.605m%2Fs)
c. Let's find h(3.1) using the data provided by the problem:
![h(3.1)=44(3.1)-0.83(3.1^2)=128.4237=x_f](https://tex.z-dn.net/?f=h%283.1%29%3D44%283.1%29-0.83%283.1%5E2%29%3D128.4237%3Dx_f)
The average velocity over the interval [3, 3.1] is :
![v_a_v_g=\frac{128.4237-124.53}{3.1-3} =38.937m/s](https://tex.z-dn.net/?f=v_a_v_g%3D%5Cfrac%7B128.4237-124.53%7D%7B3.1-3%7D%20%3D38.937m%2Fs)
d. Let's find h(3.01) using the data provided by the problem:
![h(3.1)=44(3.01)-0.83(3.01^2)=124.920117=x_f](https://tex.z-dn.net/?f=h%283.1%29%3D44%283.01%29-0.83%283.01%5E2%29%3D124.920117%3Dx_f)
The average velocity over the interval [3, 3.01] is :
![v_a_v_g=\frac{124.920117-124.53}{3.01-3} =39.0117m/s](https://tex.z-dn.net/?f=v_a_v_g%3D%5Cfrac%7B124.920117-124.53%7D%7B3.01-3%7D%20%3D39.0117m%2Fs)
e. Let's find h(3.001) using the data provided by the problem:
![h(3.001)=44(3.001)-0.83(3.001^2)=124.5690192=x_f](https://tex.z-dn.net/?f=h%283.001%29%3D44%283.001%29-0.83%283.001%5E2%29%3D124.5690192%3Dx_f)
![v_a_v_g=\frac{124.5690192-124.53}{3.001-3} =39.01917m/s](https://tex.z-dn.net/?f=v_a_v_g%3D%5Cfrac%7B124.5690192-124.53%7D%7B3.001-3%7D%20%3D39.01917m%2Fs)
Well, lets take a look at our options here. Option C is incorrect because PR doesn't equal SQ. D is wrong because it just tells us the same thing, which doesn't help us. A and B are our only answers. B is wrong because we can already see that the angle is a right angle, but we don't know if the hypo is the same, which is needed because without it, we can't tell what the other 2 angles are. A is the right answer.
Answer:
of an hour is remaining for Mariko's social studies class
Step-by-step explanation:
Given:
Total duration of Mariko's social studies class = 5/6 of an hour.
Only 3/12 of an hour has passed.
To Find:
Fraction of an hour remains for Mariko's social studies class =?
Solution:
Converting into minutes
5/6 of an hour = ![\frac{5}{6} \times (60)](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B6%7D%20%5Ctimes%20%2860%29)
=>![\frac{300}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B300%7D%7B6%7D)
=>50 minutes
So the total duration of Mariko's social studies = 50 minutes
If 3/12 of an hour passes means
Converting into minutes
=>![\frac{3}{12} \times 60](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B12%7D%20%5Ctimes%2060)
=>![\frac{180}{12}](https://tex.z-dn.net/?f=%5Cfrac%7B180%7D%7B12%7D)
=>![\frac{180}{12}](https://tex.z-dn.net/?f=%5Cfrac%7B180%7D%7B12%7D)
=> 15 minutes
15 minutes has passed
Remaining time left is
50 minutes - 15 minutes = 35 minutes left
Now converting into 35 minutes into hours we get
=> ![\frac{35}{60}](https://tex.z-dn.net/?f=%5Cfrac%7B35%7D%7B60%7D)
=>![\frac{7}{12}](https://tex.z-dn.net/?f=%5Cfrac%7B7%7D%7B12%7D)
Answer:
1 cubic meter?
Step-by-step explanation:
1 fluid ounce is about 2.95735e-5 cubic meters?
6 fluid ounces is about 0.000177441?
honestly im as confused as you are im sorry-