Answer:
$1.75
Step-by-step explanation:
The selling for each candy bar may be determined by a set of linear equations. This pair of linear equations may be solved simultaneously by using the elimination method. This will involve ensuring that the coefficient of one of the unknown variables is the same in both equations.
It may be solved by substitution in that one of the variable is made the subject of the equation and the result is substituted into the second equation
.
Let the cost of a snack bag be s and that of a candy bar be c, then if on Wednesday the students or 23 snack bags and 36 candy bars that raised $114.75 on Thursday the seventh so 37 snack bags and 36 candy bars that raised $146.25
23s + 36c = 114.75
37s + 36c = 146.25
14s = 31.5
s = $2.25
23(2.25) + 36c = 114.75
36c = 114.75 - 51.75
36c = 63
c = 63/36
= $1.75
Answer:
5. D (4,6)
6. B (7.8)
Step-by-step explanation:
5. Add the two X coordinates (6+2) and divide that by 2 (8/2=4), do the same for the two Y coordinates (4+8=12, 12/2=6)
6. Use the distance formula ![\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}\\](https://tex.z-dn.net/?f=%5Csqrt%7B%28x_%7B2%7D-x_%7B1%7D%29%5E%7B2%7D%2B%28y_%7B2%7D-y_%7B1%7D%29%5E%7B2%7D%5C%5C)
Input the coordinates ![\sqrt{(3-8)^{2}+(8-2)^{2}](https://tex.z-dn.net/?f=%5Csqrt%7B%283-8%29%5E%7B2%7D%2B%288-2%29%5E%7B2%7D)
Answer: $ 10,988.25
Step-by-step explanation:
Hi, to answer this question, first we have to multiply the original number of students scheduled to go to the trip (420) by the added students’ percentage (15%) in decimal form (divided by 100)
420 x (15/100) = 420 x 0.15 = 63 students added
Adding the number of extra students to the original number:
420+63 = 483 students (total number of students)
Finally, we have to multiply the result by the cost of each admission ticket (22.75)
483 x 22.75 = $ 10,988.25
Answer:
![\huge{ \fbox{ \sf{82}}}](https://tex.z-dn.net/?f=%20%5Chuge%7B%20%5Cfbox%7B%20%5Csf%7B82%7D%7D%7D)
Step-by-step explanation:
![\star{ \text{ \: x - 81 = 1}}](https://tex.z-dn.net/?f=%20%5Cstar%7B%20%5Ctext%7B%20%5C%3A%20x%20-%2081%20%3D%201%7D%7D)
![\text{Step \: 1 \: : Move \: 81 \: to \: right \: hand \: side \: and \: change \: it's \: sign}](https://tex.z-dn.net/?f=%20%5Ctext%7BStep%20%5C%3A%201%20%5C%3A%20%20%3A%20Move%20%5C%3A%2081%20%5C%3A%20to%20%5C%3A%20right%20%5C%3A%20hand%20%5C%3A%20side%20%5C%3A%20and%20%5C%3A%20change%20%5C%3A%20it%27s%20%5C%3A%20sign%7D)
![\hookrightarrow{ \sf{x = 1 + 81}}](https://tex.z-dn.net/?f=%20%5Chookrightarrow%7B%20%5Csf%7Bx%20%3D%201%20%2B%2081%7D%7D)
![\text{Step \: 2 \: : Add \: the \: numbers : 1 \: and \: 81}](https://tex.z-dn.net/?f=%20%5Ctext%7BStep%20%5C%3A%202%20%5C%3A%20%20%3A%20Add%20%5C%3A%20the%20%5C%3A%20numbers%20%3A%201%20%5C%3A%20and%20%5C%3A%2081%7D)
![\hookrightarrow{ \sf{x = 82}}](https://tex.z-dn.net/?f=%20%5Chookrightarrow%7B%20%5Csf%7Bx%20%3D%2082%7D%7D)
The value of x is 82
Hope I helped!
Best regards! :D
~![\sf{TheAnimeGirl}](https://tex.z-dn.net/?f=%20%5Csf%7BTheAnimeGirl%7D)