The wording of the second function may be interpreted in several differente ways. These are some:
g(x) = (x^2 +2)(x-8)
g(x)=x^2 + 2(x-8)
g(x) x^2 +2x - 8
I will work with the last one, so my system of equation is:
f(x) = - x +2.5
g(x) = x^2 + 2x - 8
f(x) = g(x) ⇒ - x + 2.5 = x^2 + 2x - 8
x^2 + 3x - 8 - x - 2.5 = 0
x^2 + 3x - 10.5 = 0
Use the quadratic formula to solve for x:
x = [ - 3 +/- √(3^2) - 4(1)(-10.5) ]/2
x = - 5.07 and x = 2.07
The answer would be 0.05 because the five is in the hundredths place
Answer:
4. A
8. D
9. B
Step-by-step explanation:
4. started with 10 points: +10
lost 20 points: -20
won 45 points: +45
10-20+45
8. 11-(-8)
=19
9. 100-(-50)-2
=150-2
=148
PLS GIVE BRAINLIEST
We have a sample that in fact represents the population.
We have to calculate the standard deviation of this population.
The difference between the standard deviation of a population comparing it to the calculation of the standard deviation of a sample is that we divide by the population side n instead of (n-1).
We have to start by calculating the mean of the population first:
Now, we can calculate the standard deviation as:
![\sigma=\sqrt[]{\dfrac{1}{n}\sum^n_{i=1}\, (x_i-\mu)^2}](https://tex.z-dn.net/?f=%5Csigma%3D%5Csqrt%5B%5D%7B%5Cdfrac%7B1%7D%7Bn%7D%5Csum%5En_%7Bi%3D1%7D%5C%2C%20%28x_i-%5Cmu%29%5E2%7D)
![\begin{gathered} \sigma=\sqrt[]{\dfrac{1}{6}((37-34)^2+(38-34)^2+(39-34)^2+(40-34)^2+(39-34)^2+(11-34)^2)} \\ \sigma=\sqrt[]{\frac{1}{6}(3^2+4^2+5^2+6^2+5^2+(-23)^2)} \\ \sigma=\sqrt[]{\frac{1}{6}(9+16+25+36+25+529)} \\ \sigma=\sqrt[]{\frac{1}{6}(640)} \\ \sigma\approx\sqrt[]{106.67} \\ \sigma\approx10.33 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Csigma%3D%5Csqrt%5B%5D%7B%5Cdfrac%7B1%7D%7B6%7D%28%2837-34%29%5E2%2B%2838-34%29%5E2%2B%2839-34%29%5E2%2B%2840-34%29%5E2%2B%2839-34%29%5E2%2B%2811-34%29%5E2%29%7D%20%5C%5C%20%5Csigma%3D%5Csqrt%5B%5D%7B%5Cfrac%7B1%7D%7B6%7D%283%5E2%2B4%5E2%2B5%5E2%2B6%5E2%2B5%5E2%2B%28-23%29%5E2%29%7D%20%5C%5C%20%5Csigma%3D%5Csqrt%5B%5D%7B%5Cfrac%7B1%7D%7B6%7D%289%2B16%2B25%2B36%2B25%2B529%29%7D%20%5C%5C%20%5Csigma%3D%5Csqrt%5B%5D%7B%5Cfrac%7B1%7D%7B6%7D%28640%29%7D%20%5C%5C%20%5Csigma%5Capprox%5Csqrt%5B%5D%7B106.67%7D%20%5C%5C%20%5Csigma%5Capprox10.33%20%5Cend%7Bgathered%7D)
Answer: the standard deviation of this population is approximately 10.33
