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Dmitry_Shevchenko [17]
3 years ago
10

Find last year’s salary if, after a 3% pay raise, this year’s salary is $30,900

Mathematics
2 answers:
saul85 [17]3 years ago
8 0

After raise, salary = 100% + 3% = 103%


103% = $30 900

1% = $30 900 ÷ 103 = $300

100% = $300 x 100 = $30 000


Answer: $30 000

Liono4ka [1.6K]3 years ago
5 0
Your answer is $30,000.
The way I have answered this is quite strange, but I'll do my best to explain it. So because we know that $30,900 is 3% than last year, we can call it 103%. This allows us to form a ratio and therefore find 100%.
30,900 : 103
÷ 103
300 : 1
× 100
30,000 : 100
Which means $30,000 is 100%, or 3% less than $30,900. I hope this helps! Let me know if it was confusing or anything :)
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The cars are waiting in line for gas Nini is 9th front the front of the line and 20 from the back how many cars are on line for
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28 cars are on the line for gas.
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3 years ago
An elementary ntimesn scaling matrix with k on the diagonal is the same as the ntimesn identity matrix with _______ exactly one
Dafna11 [192]

Answer:

exactly one, 0's, triangular matrix, product and 1.

Step-by-step explanation:

So, let us first fill in the gap in the question below. Note that the capitalized words are the words to be filled in the gap and the ones in brackets too.

"An elementary ntimesn scaling matrix with k on the diagonal is the same as the ntimesn identity matrix with EXACTLY ONE of the (0's) replaced with some number k. This means it is TRIANGULAR MATRIX, and so its determinant is the PRODUCT of its diagonal entries.​ Thus, the determinant of an elementary scaling matrix with k on the diagonal is (1).

Here, one of the zeros in the identity matrix will surely be replaced by one. That is to say, the determinants = 1 × 1 × 1 => 1. Thus, it is a a triangular matrix.

3 0
3 years ago
12
LenaWriter [7]

Answer:

2159.74

Step-by-step explanation:

you times 456 by 4 then you times that answer by the 1742%

4 0
2 years ago
Multiplying Polynomials//<br><br> Multiply- <br> 12x^4 (-5/6x^3y^2)
ElenaW [278]
12 x^{4} * (- \frac{5}{6} x^{3} y^{2})
Now multiple the coefficients and add the exponents with common bases
12 * - \frac{5}{6} = -10 \\  x^{4} +  x^{3} =  x^{7}
Now write your final expression
-10 x^{7}  y^{3}
Hope I helped!
6 0
3 years ago
What is the standard form of the equation of a line for which the length of the normal segment to the origin is 8 and the normal
jeka57 [31]
Slope of line = tan(120) = -tan(60) = - &radic;3
Distance from origin = 8

Let equation be Ax+By+C=0
then -A/B=-&radic;3, or
B=A/&radic;3.
Equation becomes
Ax+(A/&radic;3)y+C=0

Knowing that line is 8 units from origin, apply distance formula
8=abs((Ax+(A/&radic;3)y+C)/sqrt(A^2+(A/&radic;3)^2))
Substitute coordinates of origin (x,y)=(0,0)  =>
8=abs(C/sqrt(A^2+A^2/3))
Let A=1 (or any other arbitrary finite value)
solve for positive solution of C
8=C/&radic;(4/3) => C=8*2/&radic;3 = (16/3)&radic;3

Therefore one solution is
x+(1/&radic;3)+(16/3)&radic;3=0
or equivalently
&radic;3 x + y + 16 = 0

Check:
slope = -1/&radic;3  .....ok
distance from origin
= (&radic;3 * 0 + 0 + 16)/(sqrt(&radic;3)^2+1^2)
=16/2
=8  ok.

Similarly C=-16 will satisfy the given conditions.

Answer  The required equations are
&radic;3 x + y = &pm; 16 
in standard form.

You can conveniently convert to point-slope form if you wish.




4 0
3 years ago
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