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sergiy2304 [10]
3 years ago
15

Please help! Thank you!!!!!

Mathematics
1 answer:
katrin2010 [14]3 years ago
8 0

9514 1404 393

Answer:

  • f(x) = x² -3
  • g(x) = 6x +7
  • h(x) = 3^x

Step-by-step explanation:

f(x) is copied from the problem statement.

g(x) is a symbolic representation of the English wording, using x to represent "a number."

h(x) is the exponential function that corresponds to the geometric sequence in the table. It has a common ratio of 3, and a multiplier of 1 at x=0.

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Questions attached as screenshot below:Please help me I need good explanations before final testI pay attention
Nikitich [7]

The acceleration of the particle is given by the formula mentioned below:

a=\frac{d^2s}{dt^2}

Differentiate the position vector with respect to t.

\begin{gathered} \frac{ds(t)}{dt}=\frac{d}{dt}\sqrt[]{\mleft(t^3+1\mright)} \\ =-\frac{1}{2}(t^3+1)^{-\frac{1}{2}}\times3t^2 \\ =\frac{3}{2}\frac{t^2}{\sqrt{(t^3+1)}} \end{gathered}

Differentiate both sides of the obtained equation with respect to t.

\begin{gathered} \frac{d^2s(t)}{dx^2}=\frac{3}{2}(\frac{2t}{\sqrt[]{(t^3+1)}}+t^2(-\frac{3}{2})\times\frac{1}{(t^3+1)^{\frac{3}{2}}}) \\ =\frac{3t}{\sqrt[]{(t^3+1)}}-\frac{9}{4}\frac{t^2}{(t^3+1)^{\frac{3}{2}}} \end{gathered}

Substitute t=2 in the above equation to obtain the acceleration of the particle at 2 seconds.

\begin{gathered} a(t=1)=\frac{3}{\sqrt[]{2}}-\frac{9}{4\times2^{\frac{3}{2}}} \\ =1.32ft/sec^2 \end{gathered}

The initial position is obtained at t=0. Substitute t=0 in the given position function.

\begin{gathered} s(0)=-23\times0+65 \\ =65 \end{gathered}

8 0
1 year ago
herro help me .. .........................................................................................
skelet666 [1.2K]
So the easiest way to solve this is to use the straight line provided .
180=90+61+x
180=151+x
29=x
4 0
3 years ago
Read 2 more answers
The function below is written in vertex form or intercept form. Rewrite them in standard form and show your work.
lora16 [44]

Answer:

The standard form as y=5x^2+30x+41

Step-by-step explanation:

Given: A function which is written in vertex form or intercept form.

We have to re-write it  in standard form that in terms of

Given y = 5(x+3)^2-4

Squaring  using (a+b)^2=a^2+b^2+2ab , we get,  

y=5(x^2+9+6x)-4

Multiply 5 inside , we get,

y=5x^2+45+30x-4

Solving further , we get,

y=5x^2+30x+41

Thus , we have obtained the standard form as y=5x^2+30x+41







8 0
3 years ago
Read 2 more answers
Solve the following system of equations. What is one x-value of a solution? f(x)=x^(2)+7x-24 g(x)=-3x-40
Yuki888 [10]

One x- value of the solution is : -2 or -8

<h3>What is an equation?</h3>

An Equation is an algebraic statement that shows that two quantities are equal.

Analysis:

for one x-value of a solution, f(x) = g(x)

x^{2} + 7x -24 = -3x - 40

x^{2} +7x +3x -24 +40 = 0

x^{2} + 10x +16 = 0

x^{2} +8x +2x +16 = 0

x(x+8) +2(x+8) = 0

(x+2)(x+8) = 0

x = -2 or -8

In conclusion, the values of x are -2 or -8

Learn more about system of equation : brainly.com/question/14323743

#SPJ1

5 0
2 years ago
Which of the following is an arithmetic sequence?
Mashcka [7]
The following answer would be D because I’m guessing and I need the answers too sorry
6 0
3 years ago
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