Please help! Thank you!!!!!

Mathematics

1 answer:

katrin2010 [14]2 years ago

8 0

9514 1404 393

Answer:

f(x) = x² -3
g(x) = 6x +7
h(x) = 3^x

Step-by-step explanation:

f(x) is copied from the problem statement.

g(x) is a symbolic representation of the English wording, using x to represent "a number."

h(x) is the exponential function that corresponds to the geometric sequence in the table. It has a common ratio of 3, and a multiplier of 1 at x=0.

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suppose you know that over the last 10 years, the porbabiliy that your town would have at least one ma jor stor was 40%. describ

Anuta_ua [19.1K]

Answer:

The probability of a big storm is 40%.

Now, you can find a D10 (a die with 10 faces)

You can assign 4 numbers (0, 1, 2, 3) to the event "there is a major storm"

in this way, you have 40% of having a storm.

and the other 6 numbers (4, 5, 6, 7, 8, 9) to the event "there is not a major storm". This means that we have 60% of not having a storm.

now, when you roll the dice you can see if a year there will be a storm or not.

Now, you roll the dice 5 times (for the 5 years) and take note of the results and the number of storms in those 5 rolls.

Now do the same thing a bunch of times, at least 25 times.

Now, you recorded the results in each set of rolls, now see the number of sets that have at least years with storms.

Take that number and divide it by the total number of sets of data (in this case 25, for example)

The result is the probability that we are looking for.

6 0

3 years ago

A television game has 6 shows doors, of which the contests must pick 2. behind two of the doors are expensive cars, and behind t

Katyanochek1 [597]

The answer to this question:
One car probability 82/120
No car probability = 24/120
At least one car probability= 96/120

I will focus answering the 3 doors probability since the 2nd door problem is solved in the previous problem. (brainly.com/question/5761449)

No car condition
1. 1st door consolation, 2nd door consolation=, 3rd door consolation= 4/6 * 3/5 * 2/4= 24/120
This was also can be found by: (4!/1!)/ (6!/3!) = 24/120

(At least one car probability) is the opposite of (no car probability) In this case, the easier way is
100% - (no car probability) = 120/120 - 24/120= 96/120

One car probability is (At least one car probability) - (2 car probability). It will be easier to count the 2 car probability and subtract the (At least one car probability)
Two car condition:
1. 1st door car, 2nd door car, 3rd door consolation = 2/6 * 1/5 * 4/4 =8/ 120
2.1st door car, 2nd door consolation, 3rd door car =2/6 * 4/5 * 1/4 = 8/120
3. 1st door consolation, 2nd door car, 3rd door car= 4/6 * 2/5 * 1/4= 8/120
The total probability will be 8/120+ 8/120 + /120= 24/120
This was also can be found by: (2!) (4!/2!)/ (6!/3!) = 24/120

One car probability = (At least one car probability) - (2 car probability)= 96/120-24/120= 82/120

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3 years ago

If mollie can travel 250 miles in 90 minutes how far can she travel in 6 hours?

lozanna [386]

She can travel 3000 miles

7 0

3 years ago

Find the volume of the region bounded above by the elliptical paraboloid zequals=9 minus 4 x squared minus 5 y squared9−4x2−5y2

Virty [35]

Answer:

$\int\limits^1_0 \int^1_0{z} \, dA$