Answer:
Maybe if you added a coordinate chart someone could actually help you :)
Step-by-step explanation:
T = 60°
Step-by-step explanation:
Angle S = 180° - 150° = 30°
Angle U = 90°
Therefore, angle T is given by
S + U + T = 180
30° + 90° + T = 180°
or
Angle T = 60°
For the first one I got X=5
and for the second one I got X=6
It already shows that AB is 49°
in order to find ABC you must first find BC
360 - (AC + AB) = BC
360 - 156 = BC
204° = BC
NOW add BC with AB
49 + 204
253
angle ABC is 253°
now to find BAC add AB and AC
49 + 107 = 156°
angle BAC is 156°
FINALLY to find ACB add AC and CB
107 + 204
311°
angle ACB is 311°
Make a table with the angle theta as independent variable and the radius r as dependent variable:
theta radius = 4+2cos theta radius
------- -----------------------------------------
0 4+2 6
pi/6 4+2cos pi/6 = 4+2(sqrt(3)/2
Perhaps you have already plotted this using webassign (but remember that you have not shared an illustration here). (Please don't type "webassign plot" repeatedly, as it accomplishes nothing.)
Generally, when one wishes to find the area of a region defined by polar functions (as is the case here), one first determines suitable limits of integration from the finished curve and checks them through actual integration.
Which formula should you use to find the area: Look up "areas in polar coordinates," as I did. The formula is as follows:
Enclosed area = Integral from alpha to beta of (1/2)r^2 d(theta). Note that the initial radius here is 6 (since r = 4 plus 2 cos theta is 4+2 when theta = 0).
