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chubhunter [2.5K]
3 years ago
5

The histogram represents the distributions of essay scores for high school sophomores and juniors in a contest. Which statements

are true about the data used to create the histogram? Select three options.
The mean is the best comparison of the measures of center.


The juniors tended to have higher essay scores than the sophomores.


The medians of both data sets are equal.


The interquartile range is the best comparison of the measure of variability.


A histogram is the best way to show that both distributions are nearly symmetric.
Mathematics
2 answers:
Ket [755]3 years ago
8 0

Answer:

B,C, and E

Step-by-step explanation:

A histogram is a graphical illustration of information in bars of diverse heights. A histogram displays the shape and spread of continuous sample data. The true statements about the data essay scores for high school sophomores and juniors in a contest are; the juniors tended to have higher essay scores than the sophomores, the medians of both data sets are equal and the histogram is the best way to show that both distributions are nearly symmetric.

Likurg_2 [28]3 years ago
7 0

Answer:

bce

Step-by-step explanation:

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Triangle J K L is shown. Angle J L K is 105 degrees. The length of J K is 4.7 and the length of J L is 2.7.
cluponka [151]

Answer:

The approximate measure of angle K is 34°

Step-by-step explanation:

In ΔJKL

∠L = 105°

JK = 4.7

JL = 2.7

Sine Rule:

\frac{SinA}{a} = \frac{SinB}{b}= \frac{SinC}{c}

So,\frac{SinL}{JK} = \frac{SinK}{JL}\\\frac{SinL}{4.7} = \frac{SinK}{2.7}\\\frac{Sin 105}{4.7} = \frac{SinK}{2.7}\\\frac{Sin 105 \times 2.7}{4.7} = SinK\\\frac{(0.9659 \times 2.7)}{4.7} = Sin K\\\frac{2.60793}{4.7} = Sin K\\0.5549 = Sin K\\Sin^{-1}(0.5549)= K\\K = 33.70

K ≈ 34°

So, Option B is true

Hence The approximate measure of angle K is 34°

5 0
3 years ago
Please please help thanks
Gwar [14]
Answer is 2nd option

B. WYZ = WZX = ZYX

6 0
3 years ago
Last Sunday, the average temperature was 8%, percent higher than the average temperature two Sundays ago. The average temperatur
MArishka [77]

Answer: 1.08T and (1+8/100)T


Step-by-step explanation:

Given: The average temperature two Sundays ago was T degrees Celsius.

Since, last Sunday, the average temperature was 8% higher than the average temperature two Sundays ago.

⇒ The average temperature last Sunday=8\%\ of\ T+T

Since 8%=0.08

Therefore, The average temperature last Sunday=\frac{8}{100}\timesT+T

⇒ The average temperature last Sunday=T(\frac{8}{100}+1)

⇒ The average temperature last Sunday=T(0.08+1)

⇒ The average temperature last Sunday=T(1.08)

Thus, the right option is 1.08T and (1+8/100)T.

4 0
3 years ago
Cost of a CD: $17.50<br> Markup: 45%
Marizza181 [45]

Answer:

25.375

Step-by-step explanation:

17.50×45%=7.875

17.50+7.875=25.375 new price

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Find and compare the median and
Over [174]

Answer:

Median= $2.45/2

=$1.225

Mode= $2.87

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